Explanation Given: Weight of rod AB, w A B = 6 l b Weight of cart C, w C = 10 l b Length of rod AB, L = 5 f t θ = 30 0 Concept used: Energy conservation principle Calculation: Initial position : Linear momentum, L 1 = 0 Potential energy, v 1 = W A B h 1 = 6 × ( 5 2 sin 30 ) = 7.5 f t . l b Kinetic energy, T 1 = 0 Final position : Linear momentum, L 2 = W C g v C − W A B g v A B c o n s e r v a t i o n o f l i n e a r m o m e n t u m L 1 = L 2 0 = ω c g v c − ω A B g v A B . V A B = ω c ω A B v c V A B = 10 6 v c V A B = 5 3 v c .......(1) V c = − v A B + L A B 2 ω L A B = 2 ( v c + v A B ) = 2 ( 1 + 10 6 ) v c L A B = 16 3 v c .......(2) Potential energy, v 2 = − W A B L A B 2 = − 6 ( 5 2 ) = − 15 f t To determine (b) Thecorresponding velocity of cart C when rod AB is in a vertical position.

12th Edition

ISBN: 9781259977237

Author: BEER

Publisher: MCG

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Chapter 17.2, Problem 17.92P

To determine

(a)

The velocity of point B as rod AB passes through a vertical position

To determine

(b)

Thecorresponding velocity of cart C when rod AB is in a vertical position.

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Chapter 17.2, Problem 17.91P

Chapter 17.2, Problem 17.93P

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(a) The velocity of point B as rod AB passes through a vertical position

Solution Summary: The author calculates the velocity of rod at point B when rod passes through a vertical position.