The set up of two galvanic cells is given. The balanced cell equation and the value of E ° for each cell is to be stated. Concept introduction: The species at the anode undergoes oxidation while the species at the cathode undergoes reduction. The species with higher reduction potential undergoes reduction while the species with lower reduction potential undergoes oxidation. To determine: The balanced cell equation and E ° for the given galvanic cell.
The set up of two galvanic cells is given. The balanced cell equation and the value of E ° for each cell is to be stated. Concept introduction: The species at the anode undergoes oxidation while the species at the cathode undergoes reduction. The species with higher reduction potential undergoes reduction while the species with lower reduction potential undergoes oxidation. To determine: The balanced cell equation and E ° for the given galvanic cell.
Solution Summary: The author explains the balanced cell equation and the value of E° for each galvanic cell.
The set up of two galvanic cells is given. The balanced cell equation and the value of
E° for each cell is to be stated.
Concept introduction:
The species at the anode undergoes oxidation while the species at the cathode undergoes reduction. The species with higher reduction potential undergoes reduction while the species with lower reduction potential undergoes oxidation.
To determine: The balanced cell equation and
E° for the given galvanic cell.
(b)
Interpretation Introduction
Interpretation:
The set up of two galvanic cells is given. The balanced cell equation and the value of
E° for each cell is to be stated.
Concept introduction:
The species at the anode undergoes oxidation while the species at the cathode undergoes reduction. The species with higher reduction potential undergoes reduction while the species with lower reduction potential undergoes oxidation.
To determine: The balanced cell equation and
E° for the given galvanic cell.
81. a. Propose a mechanism for the following reaction:
OH
CH2=CHCHC=N
b. What is the product of the following reaction?
HO
H₂O
N=CCH2CH2CH
OH
HO
CH3CCH=CH2
H₂O
C=N
82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium ulia
For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check
the appropriate box.
Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below.
Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions
- just focus on the first stable product you expect to form in solution.
?
NH2
MgBr
Will the first product that forms in this reaction
create a new CC bond?
○ Yes
○ No
MgBr
?
Will the first product that forms in this reaction
create a new CC bond?
O Yes
O No
Click and drag to start drawing a
structure.
:☐
G
x
c
olo
Ar
HE
Predicting
As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule
with a new C - C bond as its major product:
H₂N
O
H
1.
?
2. H3O+
If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more
than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for
example to distinguish between major products with different stereochemistry.
0
If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank.
فا
Explanation
Check
Click and drag to start drawing a
structure.
Chapter 17 Solutions
Bundle: Chemistry: An Atoms First Approach, 2nd, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card
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