Chemistry for Today: General  Organic  and Biochemistry
Chemistry for Today: General Organic and Biochemistry
9th Edition
ISBN: 9781337514576
Author: Seager
Publisher: Cengage
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Chapter 17, Problem 17.53E
Interpretation Introduction

Interpretation:

The following structural characteristics are to be matched with their respective polysaccharide.

a. Contains both α(14) and α(16) glycosidic linkages

b. is composed of glucose monosaccharide units

c. Contains acetal linkages between monosaccharide units

d. is composed of highly branched molecular chains

e. is composed of unbranched molecular chains

f. Contains only α(14) glycosidic linkages

g. Contains only β(14) glycosidic linkages

Concept introduction:

A large molecule formed by combining the multiple numbers of monosaccharides is called polysaccharide. These monosaccharides can be same, known as homo-polysaccharide, or different, known as hetero-polysaccharides. A molecule with a straight chain is called linear polysaccharide and that with a branched chain is called a branched polysaccharide.

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Chapter 17 Solutions

Chemistry for Today: General Organic and Biochemistry

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