Chemistry for Today: General  Organic  and Biochemistry
Chemistry for Today: General Organic and Biochemistry
9th Edition
ISBN: 9781337514576
Author: Seager
Publisher: Cengage
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Chapter 17, Problem 17.21E
Interpretation Introduction

(a)

Interpretation:

The classification of the given monosaccharide as an aldo-or keto- triose, tetrose, pentose, or hexose is to be stated.

Concept introduction:

Carbohydrates are the polyhydroxy aldehydes or ketones or in other words, the substances that give polyhydroxy aldehydes or ketones are called carbohydrates. They can be classified on the basis of number of carbon atoms and referred as triose, tetrose, pentose and hexose when it contains three, four, five and six carbon atoms respectively. Monosaccharide is the polyhydroxy aldehyde or ketone that contains only one aldehyde or ketone unit. Monosaccharide does not undergo hydrolysis.

Interpretation Introduction

(b)

Interpretation:

The classification of the given monosaccharide as an aldo- or keto- triose, tetrose, pentose, or hexose is to be stated.

Concept introduction:

Carbohydrates are the polyhydroxy aldehydes or ketones or in other words the substances that give polyhydroxy aldehydes or ketones are called carbohydrates. They can be classified on the basis of number of carbon atoms and referred as triose, tetrose, pentose and hexose when it contains three, four, five and six carbon atoms respectively. Monosaccharide is the polyhydroxy aldehyde or ketone that contains only one aldehyde or ketone unit. Monosaccharide does not undergo hydrolysis.

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Chapter 17 Solutions

Chemistry for Today: General Organic and Biochemistry

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