Chapter 17, Problem 17.100SP

Interpretation Introduction

(a)

Interpretation:

The equilibrium constant expression for $K_{\text{sp}}$ of $\text{Ca}{\left(\text{OH}\right)}_2$ should be determined.

Concept introduction:

Solubility product is equilibrium constant for reaction that occurs when an ionic compound is dissolved to produce ions. It is represented by $K_{\text{sp}}$. Consider ${\text{A}}_x{\text{B}}_y$ to be an ionic compound. Its dissociation occurs as:

${\text{A}}_x{\text{B}}_y\rightleftharpoons x{\text{A}}^{y+}+y{\text{A}}^{x-}$

The expression for its $K_{\text{sp}}$ is as follows:

$K_{\text{sp}}={\left[{\text{A}}^{y+}\right]}^x{\left[{\text{B}}^{x-}\right]}^y$

Interpretation Introduction

(b)

Interpretation:

The equilibrium constant expression for $K_{\text{sp}}$ of ${\text{Ag}}_3{\text{PO}}_4$ should be determined.

Concept introduction:

Solubility product is equilibrium constant for reaction that occurs when an ionic compound is dissolved to produce ions. It is represented by $K_{\text{sp}}$. Consider ${\text{A}}_x{\text{B}}_y$ to be an ionic compound. Its dissociation occurs as:

${\text{A}}_x{\text{B}}_y\rightleftharpoons x{\text{A}}^{y+}+y{\text{A}}^{x-}$

The expression for its $K_{\text{sp}}$ is as follows:

$K_{\text{sp}}={\left[{\text{A}}^{y+}\right]}^x{\left[{\text{B}}^{x-}\right]}^y$

Interpretation Introduction

(c)

Interpretation:

The equilibrium constant expression for $K_{\text{sp}}$ of ${\text{BaCO}}_{\text{3}}$ should be determined.

Concept introduction:

Solubility product is equilibrium constant for reaction that occurs when an ionic compound is dissolved to produce ions. It is represented by $K_{\text{sp}}$. Consider ${\text{A}}_x{\text{B}}_y$ to be an ionic compound. Its dissociation occurs as:

${\text{A}}_x{\text{B}}_y\rightleftharpoons x{\text{A}}^{y+}+y{\text{A}}^{x-}$

The expression for its $K_{\text{sp}}$ is as follows:

$K_{\text{sp}}={\left[{\text{A}}^{y+}\right]}^x{\left[{\text{B}}^{x-}\right]}^y$

d)

Interpretation Introduction

Interpretation:

The equilibrium constant expression for $K_{\text{sp}}$ of ${\text{Ca}}_5{\left({\text{PO}}_4\right)}_3\text{OH}$ should be determined.

Concept introduction:

Solubility product is equilibrium constant for reaction that occurs when an ionic compound is dissolved to produce ions. It is represented by $K_{\text{sp}}$. Consider ${\text{A}}_x{\text{B}}_y$ to be an ionic compound. Its dissociation occurs as:

${\text{A}}_x{\text{B}}_y\rightleftharpoons x{\text{A}}^{y+}+y{\text{A}}^{x-}$

The expression for its $K_{\text{sp}}$ is as follows:

$K_{\text{sp}}={\left[{\text{A}}^{y+}\right]}^x{\left[{\text{B}}^{x-}\right]}^y$