Chemical Principles
8th Edition
ISBN: 9781337247269
Author: Steven S. Zumdahl; Donald J. DeCoste
Publisher: Cengage Learning US
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Chapter 16, Problem 77E
Interpretation Introduction
Interpretation : Formula of the given mineral should be deduced and the fraction of octahedral holes and tetrahedral holes that are filled by the various cations should be predicted.
Concept Introduction :
Ions in a crystal lattice are arranged as uniformed layers due to the space and holes of lattice in crystals. Ions formed by layers and layers are arranged to give closest packed structures.
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Chapter 16 Solutions
Chemical Principles
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- Which solid phase that is, which allotrope of carbon is more stable, graphite or diamond? You should consult some of the tables in the thermodynamics section of this text.. Both solid phases exist under normal conditions of pressure and temperature. Explain why this is so, given that one solid phase is more thermodynamically stable than the other. Do their unit cells provide any suggestion for their relative stabilities?arrow_forwardWhat is the coordination number in the cesium chloride cubic structure?arrow_forward• describe the arrangement of atoms in the common cubic crystal lattices and calculate the packing efficiency for a lattice.arrow_forward
- The free space in a metal may be found by subtracting the volume of the atoms in a unit cell from the volume of the cell. Calculate the percentage of free space in each of the three cubic lattices if all atoms in each are of equal size and touch their nearest neighbors. Which of these structures represents the most efficient packing? That is, which packs with the least amount of unused space?arrow_forwardPalladium has a cubic crystal structure in which the edge of the unit cell is 389 pm long. If the density of palladium is 12.02 g/cm3, how many palladium atoms are in a unit cell? In which of the cubic unit cells does palladium crystallize?arrow_forwardThe CsCl structure is a simple cubic array of chloride ions with a cesium ion at the center of each cubic array (see Exercise 69). Given that the density of cesium chloride is 3.97 g/cm3, and assuming that the chloride and cesium ions touch along the body diagonal of the cubic unit cell, calculate the distance between the centers of adjacent Cs+ and Cl ions in the solid. Compare this value with the expected distance based on the sizes of the ions. The ionic radius of Cs+ is 169 pm, and the ionic radius of Cl is 181 pm.arrow_forward
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