(a)
Interpretation:
Determine the structural formula from the given molecular formula:
20 aromatic
Concept Introduction:
The spatial arrangement of atom within a compound that are joined together is identified with the help of structural formula.
Explanation of Solution
The molecular formula C7 H9 N is 20 on the
(b)
Interpretation:
Determine the structural formula from the given molecular formula:
30 aromatic amines, C8 H11 N.
Concept Introduction:
The spatial arrangement of atom within a compound that are joined together is identified with the help of structural formula.
Explanation of Solution
Tertiary amines are those compounds in which three hydrogen atoms of ammonia are replaced by alkyl or aryl groups. They are represented as R3 -N or 
The molecular formula, C8 H11 N is 30 on the aromatic amine. Hence, it has six-membered ring. The nitrogen atom is attached to three groups in which one is an aryl group and the other two are methyl groups.
Thus, the structural formula for the molecular formula C8 H11 N is as below:
(c)
Interpretation:
Determine the structural formula from the given molecular formula:
10 aliphatic amines, C7 H9 N.
Concept Introduction:
The spatial arrangement of atom within a compound that are joined together is identified with the help of structural formula.
Explanation of Solution
Primary amines are those compounds in which one of the hydrogen atoms of ammonia is replaced by an alkyl or an aryl group. They are represented as 
The molecular formula C7 H9 N is 10 on the aliphatic amine. Hence it has
(d)
Interpretation:
Determine the structural formula from the given molecular formula:
A chiral 10 amine, C4 H11 N.
Concept Introduction:
The spatial arrangement of atom within a compound that are joined together is identified with the help of structural formula.
Explanation of Solution
Primary amines are those compounds in which one of the hydrogen atoms of ammonia is replaced by an alkyl or aryl group. They are represented as
The carbon atom attach to four different group is called a chiral atom. When a molecule possesses such atom, then they are not superimposable on their mirror image.
The molecular formula C4 H11 N is 10 on the aliphatic amine, and it is a chiral molecule. Hence, the chiral carbon atom is attached to four different groups, which include -NH2 group, the -CH3 group, the -CH2 group and the -H group. The structural formula of C4 H11 N is as below:
(e)
Interpretation:
Determine the structural formula from the given molecular formula:
A 30 heterocyclic amine, C5 H11 N.
Concept Introduction:
The spatial arrangement of atom within a compound that are joined together is identified with the help of structural formula.
Explanation of Solution
Tertiary amines are those compounds in which three hydrogen atoms of ammonia are replaced by alkyl or aryl groups. They are represented as R3 -N or 
The carbon atom attach to four different group is called a chiral atom. When a molecule possesses such atom, then they are not superimposable on their mirror image.
The molecular formula C5 H11 N is 30 on the heterocyclic amine. This structure has a five membered heterocyclic ring. This ring contains four carbons and one nitrogen atom. The nitrogen atom in the ring is bonded to the methyl group. The structural formula of C4 H11 N is as below:
(f)
Interpretation:
Determine the structural formula from the given molecular formula:
A trisubstituted 10 aromatic amine, C9 H13 N.
Concept Introduction:
The spatial arrangement of atom within a compound that are joined together is identified with the help of structural formula.
Explanation of Solution
Primary amines are those compounds in which one of the hydrogen atoms of ammonia is replaced by an alkyl or aryl group. They are represented as
The molecular formula C9 H13 N is tri substituted 10 on the aromatic amine. Hence, it has six membered rings with three methyl groups. The structural formula of C5 H13 N is as below:
(g)
Interpretation:
Determine the structural formula from the given molecular formula:
A chiral quaternary ammonium salt, C9 H22 NCl.
Concept Introduction:
The spatial arrangement of atom within a compound that are joined together is identified with the help of structural formula.
Explanation of Solution
Quaternary amines are those compounds in which all four of the hydrogen atoms of the ammonium ion are replaced by an alkyl or aryl group. It is an ionic quaternary salt.
When the carbon atom is attached to four different groups, it is called a chiral atom. When a molecule possesses such an atom, then it is not super imposable on its mirror image.
The molecular formula C9 H22 NCl is a quaternary amine and it is a chiral molecule. Hence, the chiral nitrogen atom is attached to four different groups, which include -CH2 CH3 group, the -CH2 CH2 CH3 group, the -CH3 CHCH3 group, and the -CH3 group. Therefore, the quaternary ammonium salt of C9 H22 NCl is as below:
Want to see more full solutions like this?
Chapter 16 Solutions
Introduction to General, Organic and Biochemistry
- Complete the mechanism for the E1 reaction below by following the directions written above each of the five boxes. Be sure to include lone pair electrons and nonzero formal charges. 1st attempt Y 0 + Provide the missing curved arrow notation. 01: See Periodic Table See Hint H C Br Iarrow_forwardPlease help answer number 2. Thanks in advance.arrow_forwardHow do I explain this? Thank you!arrow_forward
- When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z) is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm. The 13C NMR and DEPT spectra are provided. Draw the structure of the product as the resonance contributor lacking any formal charges. 13C NMR DEPT 90 200 160 120 80 40 0 200 160 120 80 40 0 DEPT 135 T 200 160 120 80 40 0 Draw the unknown amide. Select Dow Templates More Fragearrow_forwardIdentify the unknown compound from its IR and proton NMR spectra. C4H6O: 'H NMR: 82.43 (1H, t, J = 2 Hz); 8 3.41 (3H, s); 8 4.10 (2H, d, J = 2 Hz) IR: 2125, 3300 cm¹ The C4H6O compound liberates a gas when treated with C2H5 MgBr. Draw the unknown compound. Select Draw с H Templates Morearrow_forwardPlease help with number 6 I got a negative number could that be right?arrow_forward
- 1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.arrow_forwardGive the product of the bimolecular elimination from each of the isomeric halogenated compounds. Reaction A Reaction B. КОВ CH₂ HotBu +B+ ко HOIBU +Br+ Templates More QQQ Select Cv Templates More Cras QQQ One of these compounds undergoes elimination 50x faster than the other. Which one and why? Reaction A because the conformation needed for elimination places the phenyl groups and to each other Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other. ◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other. Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.arrow_forwardFive isomeric alkenes. A through each undergo catalytic hydrogenation to give 2-methylpentane The IR spectra of these five alkenes have the key absorptions (in cm Compound Compound A –912. (§), 994 (5), 1643 (%), 3077 (1) Compound B 833 (3), 1667 (W), 3050 (weak shoulder on C-Habsorption) Compound C Compound D) –714 (5), 1665 (w), 3010 (m) 885 (3), 1650 (m), 3086 (m) 967 (5), no aharption 1600 to 1700, 3040 (m) Compound K Match each compound to the data presented. Compound A Compound B Compound C Compound D Compoundarrow_forward
- 7. The three sets of replicate results below were accumulated for the analysis of the same sample. Pool these data to obtain the most efficient estimate of the mean analyte content and the standard deviation. Lead content/ppm: Set 1 Set 2 Set 3 1. 9.76 9.87 9.85 2. 9.42 9.64 9.91 3. 9.53 9.71 9.42 9.81 9.49arrow_forwardDraw the Zaitsev product famed when 2,3-dimethylpentan-3-of undergoes an El dehydration. CH₂ E1 OH H₁PO₁ Select Draw Templates More QQQ +H₂Oarrow_forwardComplete the clean-pushing mechanism for the given ether synthesia from propanol in concentrated sulfurica140°C by adding any mining aloms, bands, charges, nonbonding electron pairs, and curved arrows. Draw hydrogen bonded to cayan, when applicable. ore 11,0 HPC Step 1: Draw curved arrows Step 2: Complete the intend carved Q2Q 56 QQQ Step 3: Complete the intermediate and add curved Step 4: Modify the structures to draw the QQQ QQQarrow_forward
Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning