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Concept explainers
(a)
Interpretation:
The name of the following aldehyde is to be determined.
Concept Introduction:
While naming the
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Answer to Problem 16.32P
The name of the compound is 3,3-dimethylbutanal.
Explanation of Solution
The given molecular formula of the aldehyde is:
Here the numbering of the carbon chain will start from the right where -CHO group is present. It can be clearly seen that the longest carbon chain containing the aldehyde group consists of four carbon atoms and two methyl substituentsare attached to carbon number 3.
Therefore, the name of the compound becomes 3,3-dimethylbutanal.
(b)
Interpretation:
The name of the following aldehyde is to be determined.
Concept Introduction:
While naming the aldehydes as per the IUPAC nomenclature, the naming of the compounds is done by adding a suffix-al in the end of the name. Firstly, one will find the longest chain that contains the -CHO group and then change the -e ending of the parent alkane chain to -al suffix. Then, the numbering of the chain or the ring is done in such a way so as to put the -CHO group at carbon number 1 followed by omitting this number from the name. Thereafter, apply all other rules of nomenclature as usual.
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Answer to Problem 16.32P
The name of the compound is 4-ethylheaxanal.
Explanation of Solution
The given molecular formula of the aldehyde is:
Here the numbering of the carbon chain will start from the right where -CHO group is present. It can be clearly seen that the longest carbon chain containing aldehydic group consists of six carbon atoms and an ethyl substituent is attached to carbon number4.
Therefore, the name of the compound becomes 4-ethylhexanal.
(c)
Interpretation:
The name of the following aldehyde is to be determined.
Concept Introduction:
While naming the aldehydes as per the IUPAC nomenclature, the naming of the compounds is done by adding a suffix-al in the end of the name. Firstly, one will find the longest chain that contains the -CHO group and then change the -e ending of the parent alkane chain to -al suffix. Then, the numbering of the chain or the ring is done in such a way so as to put the -CHO group at carbon no. 1 followed by omitting this number from the name. Thereafter, apply all other rules of nomenclature as usual.
![Check Mark](/static/check-mark.png)
Answer to Problem 16.32P
The name of the compound is 3,4-dimethyloctanal.
Explanation of Solution
The given molecular formula of the aldehyde is:
Here, the numbering of the carbon chain will start from the right where -CHO group is present. It can be clearly seen that the longest carbon chain containing the aldehyde group consists of eight carbon atoms and a methyl substituent is attached to carbon number 3 as well as carbon number 4.
Therefore, the name of the compound becomes 3,4-dimethyloctanal.
(d)
Interpretation:
The name of the following aldehyde is to be determined.
Concept Introduction:
While naming the aldehydes as per the IUPAC nomenclature, the naming of the compounds is done by adding a suffix-al in the end of the name. Firstly, one will find the longest chain that contains the -CHO group and then change the -e ending of the parent alkane chain to -al suffix. Then, the numbering of the chain or the ring is done in such a way so as to put the -CHO group at carbon number 1 followed by omitting this number from the name. Thereafter, apply all other rules of nomenclature as usual.
![Check Mark](/static/check-mark.png)
Answer to Problem 16.32P
The name of the compound is 3-butylheptanal.
Explanation of Solution
The given molecular formula of the aldehyde can be written as follows:
Here, the numbering of the carbon chain will start from the right where -CHO group is present. It can be clearly seen that the longest carbon chain containing the aldehyde group consists of seven carbon atoms and abutyl substituent is attached to carbon number 3.
Therefore, the name of the compound becomes 3-butylheptanal.
(e)
Interpretation:
The name of the following aldehyde is to be determined.
Concept Introduction:
While naming the aldehydes as per the IUPAC nomenclature, the naming of the compounds is done by adding a suffix-al in the end of the name. Firstly, one will find the longest chain that contains the -CHO group and then change the -e ending of the parent alkane chain to -al suffix. Then, the numbering of the chain or the ring is done in such a way so as to put the -CHO group at carbon no. 1 followed by omitting this number from the name. Thereafter, apply all other rules of nomenclature as usual.
![Check Mark](/static/check-mark.png)
Answer to Problem 16.32P
The name of the compound is 3-ethylbenzaldehyde.
Explanation of Solution
The given molecular formula of the aldehyde is:
The name of the compound will be 3-ethylbenzaldehyde as the ethyl group is attached to the carbon number 3 of the parent molecule which is benzaldehyde. The benzene ring when attached to -CHO group is known as benzaldehyde.
The naming of the molecule will start from the carbon to which aldehydic group is attached.
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Chapter 16 Solutions
General, Organic, & Biological Chemistry
- Q1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. + CI OH woཡི།༠w Br H مه D CI ပ။ Br H, Br Br H₂N OMe R IN Ill N S H CI Br CI CI D OH H 1/111arrow_forwardDraw the two products of the reaction. H₂C. CH₂ H :0: CH3 CH₂ +1arrow_forwardShow work. Don't give Ai generated solutionarrow_forward
- ASP.....arrow_forwardQuestion 7 (10 points) Identify the carboxylic acid present in each of the following items and draw their structures: Food Vinegar Oranges Yogurt Sour Milk Pickles Acid Structure Paragraph ✓ BI UAE 0118 + v Task: 1. Identify the carboxylic acid 2. Provide Name 3. Draw structure 4. Take a picture of your table and insert Add a File Record Audio Record Video 11.arrow_forwardCheck the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 IZ IN Molecule 4 Molecule 5 ZI none of the above ☐ Molecule 3 Х IN www Molecule 6 NH Garrow_forward
- Highlight each chiral center in the following molecule. If there are none, then check the box under the drawing area. There are no chiral centers. Cl Cl Highlightarrow_forwardA student proposes the following two-step synthesis of an ether from an alcohol A: 1. strong base A 2. R Is the student's proposed synthesis likely to work? If you said the proposed synthesis would work, enter the chemical formula or common abbreviation for an appropriate strong base to use in Step 1: If you said the synthesis would work, draw the structure of an alcohol A, and the structure of the additional reagent R needed in Step 2, in the drawing area below. If there's more than one reasonable choice for a good reaction yield, you can draw any of them. ☐ Click and drag to start drawing a structure. Yes No ロ→ロ 0|0 G Х D : ☐ பarrow_forwardटे Predict the major products of this organic reaction. Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products. ☐ ☐ : ☐ + NaOH HO 2 Click and drag to start drawing a structure.arrow_forward
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