Chapter 16, Problem 16.122CHP

Interpretation Introduction

Interpretation:

$\Delta H°$ and $\Delta S°$ for the given reaction has to be calculated.

$N{H}_{3(aq)}+{\text{ H}}_2{O}_{(l)}\stackrel{}{\rightleftharpoons }N{H}_{4(aq)}+{\text{ OH}}^{-}{}_{(aq)}$

Concept Introduction:

• $\Delta G°$ refers to free energy change under standard conditions.  It is represented as,

$\Delta G°=\Delta \text{H}°\text{-T}\Delta \text{S}°$

Where,

$\begin{array}{l}\Delta S°=\text{ standard entropy change}\\ \Delta H°=\text{ standard enthalpy change}\\ \text{T}\text{=}\text{ Temperature}\end{array}$

Standard free energy change and equilibrium constant of a reaction involving gases are related as

$\Delta G°=-\text{ RT ln K}$

Where,

$\begin{array}{l}\Delta G°=\text{ standard free energy change}\\ R=\text{ Universal gas constant}\\ \text{T}=\text{ Temperature}\\ \text{K}\text{= equilibrium constant}\end{array}$