Chapter 16, Problem 16.118CHP

Interpretation Introduction

Interpretation:

Given the total pressure of decomposition reaction involving $N{H}_{4}HS$ standard free energy formation of $N{H}_{4}HS$ at $25°C$ has to be calculated.

Concept Introduction:

Standard free energy change of a reaction is related to equilibrium constant of a reaction involving a gas as,

$\Delta G°=-{\text{ RT ln K}}_p$

Where,

$\begin{array}{l}\Delta G°=\text{ standard free energy change}\\ R=\text{ Universal gas constant}\\ \text{T}=\text{ Temperature}\\ {\text{K}}_p\text{= equilibrium constant related to partial pressure of gases in the reaction}\end{array}$