Chapter 15.3, Problem 15.5P

(a)

Interpretation Introduction

Interpretation:

Molarity of each ion found in $\text{0}{\text{.050 M MgCl}}_2$ has to be calculated.

Concept Introduction:

Molarity is quantitatively defined as moles of solute in one liter of solution. For example, $\text{0}{\text{.070 M AlCl}}_3$ indicates that in $1\text{ L}$ the moles of ${\text{AlCl}}_3$ is $\text{0}\text{.070 mol}$. The formula to evaluate volume from molarity is given as follows:

  $M=\frac{n}{V}$

Here,

$V$ represents volume.

$M$ represents molarity.

$n$ represents number of moles.

(b)

Interpretation Introduction

Interpretation:

Molarity of each ion found in $\text{0}{\text{.070 M AlCl}}_3$ has to be calculated.

Concept Introduction:

Refer to part (a).