Chapter 15, Problem 54AE

Interpretation Introduction

Interpretation:

Molarity of $\text{25}\text{.22 mL}{\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ required to neutralize with $\text{35}\text{.22 mL}$ of $\text{0}\text{.313 M NaOH}$ has to be calculated.

Concept Introduction:

Molarity is quantitatively defined as moles of solute in one liter of solution. For example $\text{0}{\text{.070 M AlCl}}_3$ indicates that in $1\text{ L}$ the moles of ${\text{AlCl}}_3$ is $\text{0}\text{.070 mol}$. The formula to evaluate molarity is given as follows:

  $M=\frac{n}{V}$

Here,

$V$ represents volume.

$M$ represents molarity.

$n$ represents number of moles.