FOUNDATIONS OF COLLEGE CHEM +KNEWTONALTA
FOUNDATIONS OF COLLEGE CHEM +KNEWTONALTA
15th Edition
ISBN: 9781119797807
Author: Hein
Publisher: WILEY
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Chapter 15, Problem 71AE
Interpretation Introduction

Interpretation:

Volume of 0.60 M HCl is required to be added to neutral sodium rhodizonate to form 500 mL of solution with pH of 2.8 has to be calculated.

Concept Introduction:

The acidity strength is quantified by the magnitude of a parameter called pH. The strong acids tend to lower values of pH. This is since pH represents the negative logarithm of the concentration of H+ ion. So higher the concentration of H+ ion lower will be pH.

The expression to evaluate pH is as follows:

  pH=log[H+]

Here,

[H+] denotes concentration of H+ ions.

The dilution formula is given as follows:

  M1V1=M2V2

Here,

M1 denotes molarity of  initial solution before dilution.

V1 denotes the volume before dilution.

M2 denotes molarity of final solution after dilution.

V2 denotes volume after dilution.

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Chapter 15 Solutions

FOUNDATIONS OF COLLEGE CHEM +KNEWTONALTA

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