Chapter 15, Problem 65AE

(a)

Interpretation Introduction

Interpretation:

The indicated equation has to be balanced.

  ${\text{H}}_2{\text{SO}}_{\text{4}}+\text{NaOH}\to {\text{Na}}_2{\text{SO}}_{\text{4}}+{\text{H}}_{\text{2}}\text{O}$

Concept Introduction:

To balance an equation, one starts with the most complex chemical formula and then places the appropriate coefficient so as to make the stoichiometric coefficient equal on each side As per law of conservation of mass.

(b)

Interpretation Introduction

Interpretation:

Volume of $\text{0}\text{.10 }M\text{ NaOH}$ required to react with $0.0050{\text{ mol H}}_2{\text{SO}}_{\text{4}}$ has to be calculated.

Concept Introduction:

Molarity is quantitatively defined as moles of solute in one liter of solution. For example $\text{0}{\text{.070 M AlCl}}_3$ indicates that in $1\text{ L}$ the moles of ${\text{AlCl}}_3$ is $\text{0}\text{.070 mol}$. The formula to evaluate volume from molarity is given as follows:\

  $V=\frac{n}{M}$

Here,

$V$ represents volume.

$M$ represents molarity.

$n$ represents number of moles.

(c)

Interpretation Introduction

Interpretation:

Mass of ${\text{Na}}_2{\text{SO}}_{\text{4}}$ has to be calculated.

Concept Introduction:

Refer to part (b).