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(a)
Interpretation:Whether the arrows representing the movement of electrons in molecules A to D leading to a resonance form is correct or not needs to be determined.
Concept Introduction:VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pair or lone pair present in it. According to VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry.
The resonance is the phenomenon in which if all the properties cannot explain by one structure, it can be shown in two or more structures by the shifting of pi bonds or lone pair but there is no change in sigma bond and position of atoms.
(b)
Interpretation:Thetwo resonance forms of nitrite ion
Concept Introduction:VSEPR theory stands for Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pair or lone pair present in it. According to VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pair and bond pair, the molecular geometry can be determined with the help of below table.
| Number of hybridizations | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
(c)
Interpretation:TheLewis octet and valence shell expanded resonance forms of
Concept Introduction:VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pair or lone pair present in it. According to VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pair and bond pair, the molecular geometry can be determined with the help of below table.
| Number of hybridization | Bond pair | Lone pair | Geometry |
| 2 | 2 | 0 | Linear |
| 2 | 1 | 1 | Linear |
| 3 | 3 | 0 | Trigonal planar |
| 3 | 2 | 1 | Bent |
| 4 | 4 | 0 | Tetrahedral |
| 4 | 3 | 1 | Trigonal pyramidal |
| 4 | 2 | 2 | Bent |
| 5 | 5 | 0 | Trigonal bipyramidal |
| 5 | 4 | 1 | See saw |
| 5 | 3 | 2 | T shaped |
| 5 | 2 | 3 | Linear |
| 6 | 6 | 0 | Octahedral |
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Chapter 1 Solutions
ORGANIC CHEMISTRY (LL)-PACKAGE
- Draw the Lewis structure of C2H4Oarrow_forwarda) 5. Circle all acidic (and anticoplanar to the Leaving group) protons in the following molecules, Solve these elimination reactions, and identify the major and minor products where appropriate: 20 points + NaOCH3 Br (2 productarrow_forwardNonearrow_forward
- Dr. Mendel asked his BIOL 260 class what their height was and what their parent's heights were. He plotted that data in the graph below to determine if height was a heritable trait. A. Is height a heritable trait? If yes, what is the heritability value? (2 pts) B. If the phenotypic variation is 30, what is the variation due to additive alleles? (2 pts) Offspring Height (Inches) 75 67.5 60 52.5 y = 0.9264x + 4.8519 55 60 65 MidParent Height (Inches) 70 75 12pt v V Paragraph B IUA > AT2 v Varrow_forwardExperiment: Each team will be provided with 5g of a mixture of acetanilide and salicylic acid. You will divide it into three 1.5 g portions in separate 125 mL Erlenmeyer flasks savıng some for melting point analysis. Dissolve the mixture in each flask in ~60mL of DI water by heating to boiling on a hotplate. Take the flasks off the hotplate once you have a clear solution and let them stand on the bench top for 5 mins and then allow them to cool as described below. Sample A-Let the first sample cool slowly to room temperature by letting it stand on your lab bench, with occasional stirring to promote crystallization. Sample B-Cool the second sample 1n a tap-water bath to 10-15 °C Sample C-Cool the third sample in an ice-bath to 0-2 °C Results: weight after recrystalization and melting point temp. A=0.624g,102-115° B=0.765g, 80-105° C=1.135g, 77-108 What is the percent yield of A,B, and C.arrow_forwardRel. Intensity Q 1. Which one of the following is true of the compound whose mass spectrum is shown here? Explain how you decided. 100 a) It contains chlorine. b) It contains bromine. c) It contains neither chlorine nor bromine. 80- 60- 40- 20- 0.0 0.0 TT 40 80 120 160 m/z 2. Using the Table of IR Absorptions how could you distinguish between these two compounds in the IR? What absorbance would one compound have that the other compound does not? HO CIarrow_forward
- Illustrate reaction mechanisms of alkenes with water in the presence of H2SO4, detailing each step of the process. Please show steps of processing. Please do both, I will thumb up for sure #1 #3arrow_forwardDraw the following molecule: (Z)-1-chloro-1-butenearrow_forwardIdentify the molecule as having a(n) E, Z, cis, or trans configuration. CH3 H₁₂C ○ E ○ z ○ cis transarrow_forward
- Identify the molecule as having a(n) E, Z, cis, or trans configuration. H₂C- CH3 О Е ○ cis ○ transarrow_forwardThe decomposition of dinitrogen pentoxide according to the equation: 50°C 2 N2O5(g) 4 NO2(g) + O2(g) follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial concentration of N2O5 is 0.275 M, determine: the final concentration of N2O5 after 180 seconds. ...arrow_forwardDon't used hand raitingarrow_forward
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning