ORGANIC CHEMISTRY (LL)-PACKAGE
8th Edition
ISBN: 9781319316389
Author: VOLLHARDT
Publisher: MAC HIGHER
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Chapter 1, Problem 53P
(a)
Interpretation Introduction
Interpretation: The condensed formulas need to be converted into the Lewis dot structures. The geometry and hybridization of the bold carbon atom in A and B needs to be determined. Whether hybridization changes during the reaction or not needs to be determined.
Concept Introduction: The Lewis dot structure is used to explain the arrangement of all the atoms in the molecule and distribution of total number of valence electrons in the molecule. The distribution of electrons takes place in such a way that all the atoms have complete octet.
(b)
Interpretation Introduction
Interpretation: The condensed formulas need to be drawn as a bond line structures.
Concept Introduction: In the bond line formulas, the bonds between the atoms within the molecules are represented by straight lines.
(c)
Interpretation Introduction
Interpretation: The polar bonds need to be identified.
Concept Introduction: The bond between the two atoms is said to be polar if there is difference in the electronegativity in the two atoms. The more electronegative atom gets a partial negative charge and electropositive atom gets a partial positive charge.
(d)
Interpretation Introduction
Interpretation: The given reaction needs to be represented with the help of flow of electrons for the two steps.
Concept Introduction: The flow of electrons in any molecule takes place from negative to positive charge.
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Arrange the solutions in order of increasing acidity. (Note that K (HF) = 6.8 x 10 and K (NH3) = 1.8 × 10-5)
Rank solutions from least acidity to greatest acidity. To rank items as equivalent, overlap them.
▸ View Available Hint(s)
Least acidity
NH&F NaBr NaOH
NH,Br NaCIO
Reset
Greatest acidity
1. Consider the following molecular-level diagrams of a titration.
O-HA molecule
-Aion
°°
о
°
(a)
о
(b)
(c)
(d)
a. Which diagram best illustrates the microscopic representation for the
EQUIVALENCE POINT in a titration of a weak acid (HA) with sodium.
hydroxide?
(e)
Answers to the remaining 6 questions will be hand-drawn on paper and submitted as a single
file upload below:
Review of this week's reaction:
H₂NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H₂O --->
H₂NC(=NH)N(CH3)CH2COOH (creatine)
Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing
the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts)
Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts)
Q9. Explain with drawing why the C-N bond shown in creatine structure below can or cannot rotate. (3
pts)
NH2(C=NH)-N(CH)CH2COOH
This bond
Q10. Draw two tautomers of creatine using line structures. (Note: this question is valid because problem
Q9 is valid). (4 pts)
Q11. Mechanism. After seeing and understanding the mechanism of creatine synthesis, students should
be ready to understand the first half of one of the Grignard reactions presented in a past…
Chapter 1 Solutions
ORGANIC CHEMISTRY (LL)-PACKAGE
Ch. 1.3 - Prob. 1.1ECh. 1.3 - Prob. 1.2ECh. 1.3 - Prob. 1.3ECh. 1.3 - Prob. 1.4ECh. 1.3 - Prob. 1.5ECh. 1.4 - Prob. 1.6ECh. 1.4 - Prob. 1.8TIYCh. 1.5 - Prob. 1.9ECh. 1.5 - Prob. 1.11TIYCh. 1.6 - Prob. 1.12E
Ch. 1.6 - Prob. 1.13ECh. 1.7 - Prob. 1.15TIYCh. 1.8 - Prob. 1.16ECh. 1.8 - Prob. 1.18TIYCh. 1.9 - Prob. 1.19ECh. 1.9 - Prob. 1.20ECh. 1.9 - Prob. 1.21ECh. 1.9 - Prob. 1.22ECh. 1 - Prob. 25PCh. 1 - Prob. 26PCh. 1 - Prob. 27PCh. 1 - Prob. 28PCh. 1 - Prob. 29PCh. 1 - Prob. 30PCh. 1 - Prob. 31PCh. 1 - Prob. 32PCh. 1 - Prob. 33PCh. 1 - Prob. 34PCh. 1 - Prob. 35PCh. 1 - Prob. 36PCh. 1 - Prob. 37PCh. 1 - Prob. 38PCh. 1 - Prob. 39PCh. 1 - Prob. 40PCh. 1 - Prob. 41PCh. 1 - Prob. 42PCh. 1 - Prob. 43PCh. 1 - Prob. 44PCh. 1 - Prob. 45PCh. 1 - Prob. 46PCh. 1 - Prob. 47PCh. 1 - Prob. 48PCh. 1 - Prob. 49PCh. 1 - Prob. 50PCh. 1 - Prob. 51PCh. 1 - Prob. 52PCh. 1 - Prob. 53PCh. 1 - Prob. 54PCh. 1 - Prob. 55PCh. 1 - Prob. 56PCh. 1 - Prob. 57PCh. 1 - Prob. 58P
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