Biochemistry
9th Edition
ISBN: 9781305961135
Author: Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher: Cengage Learning
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Chapter 15, Problem 16RE
Interpretation Introduction
Interpretation:
The value of 
is to be calculated for the given reactions using the free-energy values from the 
.
Concept introduction:
Gibbs free energy is the standard free energy that complements the production of 
mole of that substance from its component elements, at their standard states.
The symbol of standard Gibbs free energy is 
.
The mitochondrion is called the powerhouse of the cell.
Mitochondria is used for the synthesis of 
that is used to store the energy
Expert Solution & Answer
Answer to Problem 16RE
Solution:
The reaction will not proceed in the direction as stated. The value of 
is 
.
The reaction will proceed in the direction as stated. The value of is 
.
The reaction will not proceed in the direction as stated. The value of is 
.
The reaction will proceed in the direction as stated. The value of is 
.
Explanation of Solution
Given information:
a) For predicting the reaction and calculating the value of :
From the table 
in the book,
Also,
On reversing the second reaction,
Now add the two reactions and their Gibbs free energies as follows:
Substitute the value as follows:
for and
for
Hence, the reaction will not be in the direction as written.
b) For predicting the reaction and calculating the value of :
From the table in the book,
Also,
On reversing the second reaction,
Now add the two reactions and their Gibbs free energies as follows:
Substitute the value as follows:
for and
for 
Hence, the reaction will be in the direction as written.
c) For predicting the reaction and calculating the value of :
From the table in the book,
Also,
On reversing the second reaction,
Now add the two reactions and their Gibbs free energies as follows:
Substitute,
For and
For
.
So,
Hence, the reaction will not be in the direction as written.
d) For predicting the reaction and calculating the value of :
From the table in the book,
Also,
On reversing the second reaction,
Now add the two reactions and their Gibbs free energies as follows:
Substitute the value as follows:
for 
and
for.
Hence, the reaction will be in the direction as written.
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Students have asked these similar questions
Solve correctly please with explanation need.
61. MATHEMATICAL For the following aspartase reaction (see Ques-
tion 28) in the presence of the inhibitor hydroxymethylaspar-
tate, determine K and whether the inhibition is competitive or
noncompetitive.
[S]
(molarity)
V, No Inhibitor
(arbitrary units)
V, Inhibitor Present
(same arbitrary units)
:21×10¹01 0.026 TOIV 0.0109 9
5 X 10
0.092
0.040
0.086
0.120
10-3
IPO?
2.5 10-³
5×10 211 0.150 09M
ein
5 X 10-3
0.165
20 mys
0.142
ENZYME KINETICS ANALYSIS
of 6
Xanthine oxidase (XO) is the enzyme that catalyzes the synthesis of uric acid, which in excess
causes gouty arthritis. The inhibition of this enzyme is therefore critical in its treatment. A student
researcher is investigating the inhibitory effects of kaempferol (Kmp) and chlorogenic acid (Cha) on XO
which uses xanthine (Xan) as substrate. Table 1 below shows the enzyme kinetic data. Construct the
Lineweaver-Burk plot complete with the linear regression analvsis. Fill in the needed information on Table
2 and paste a copy of your Lineweaver-Burk plot. submit the picture of your output in PNG or JPG format.
Table 1. Enzyme Kinetic Data
Velocity, mM/s
[S], mM
Хan
Kmp
Cha
0.492
0.0678
0.0351
0.0615
0.211
0.0531
0.0261
0.0451
0.087
0.0298
0.0157
0.0211
0.048
0.0195
0.0091
0.0142
0.029
0.0127
0.0067
0.0081
Table 2. Enzyme Kinetic Parameters
Xanthine
Kaempferol
Chlorogenic acid
Parameters
Vmax
Км
Type of Inhibition
Mode of Binding
NA
NA
Lineweaver-Burk Plot
Chapter 15 Solutions
Biochemistry
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