Organic And Biological Chemistry
7th Edition
ISBN: 9781305081079
Author: STOKER, H. Stephen (howard Stephen)
Publisher: Cengage Learning,
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Chapter 15, Problem 15.71EP
Interpretation Introduction
Interpretation: To determine the fate of the fumarate formed in the urea cycle.
Concept introduction: A urea cycle is a cyclic biochemical pathway that involves the production of urea using ammonium ions and aspartate molecules as nitrogen sources. The desired product of the urea cycle is urea. It constitutes 4 steps. In step 1 carbamoyl phosphate transfers its carbamoyl group to ornithine to produce citrulline. Citrulline then condenses with aspartate in the second step to form argininosuccinate which then cleaves in the third step to form arginine and fumarate. In the final step, arginine reacts with water to produce urea.
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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10
Consider the following reaction:
CH3OH(g)
CO(g) + 2H2(g)
(Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.)
Part A
Calculate AG for this reaction at 25 °C under the following conditions:
PCH₂OH
Pco
PH2
0.815 atm
=
0.140 atm
0.170 atm
Express your answer in kilojoules to three significant figures.
Ο ΑΣΦ
AG = -150
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kJ
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Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship:
AGrxn = AGrxn + RTInQ,
AGxn+RTInQ,
where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a
is the reaction quotient.
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Chapter 15 Solutions
Organic And Biological Chemistry
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