Structure of an aldotetrose has to be drawn. Concept Introduction: Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses. The number of carbon atoms present in the chain characterize the monosaccharide. They are given below. Carbon chain with three carbon atoms is triose. Carbon chain with four carbon atoms is tetrose. Carbon chain with five carbon atoms is as pentose. Carbon chain with six carbon atoms is as hexose.

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Answer 1

Question

Chapter 14.2, Problem 14.4P

(a)

Interpretation Introduction

Interpretation:

Structure of an aldotetrose has to be drawn.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

(b)

Interpretation Introduction

Interpretation:

Structure of a ketopentose has to be drawn.

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

Structure of an aldohexose has to be drawn.

Concept Introduction:

Refer part (a).

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(a 4 shows scanning electron microscope (SEM) images of extruded actions of packing bed for two capillary columns of different diameters, al 750 (bottom image) and b) 30-μm-i.d. Both columns are packed with the same stationary phase, spherical particles with 1-um diameter. A) When the columns were prepared, the figure shows that the column with the larger diameter has more packing irregularities. Explain this observation. B) Predict what affect this should have on band broadening and discuss your prediction using the van Deemter terms. C) Does this figure support your explanations in application question 33? Explain why or why not and make any changes in your answers in light of this figure. Figure 4 SEM images of sections of packed columns for a) 750 and b) 30-um-i.d. capillary columns.³

fcrip = ↓ bandwidth Il temp 32. What impact (increase, decrease, or no change) does each of the following conditions have on the individual components of the van Deemter equation and consequently, band broadening? Increase temperature Longer column Using a gas mobile phase instead of liquid Smaller particle stationary phase Multiple Paths Diffusion Mass Transfer

34. Figure 3 shows Van Deemter plots for a solute molecule using different column inner diameters (i.d.). A) Predict whether decreasing the column inner diameters increase or decrease bandwidth. B) Predict which van Deemter equation coefficient (A, B, or C) has the greatest effect on increasing or decreasing bandwidth as a function of i.d. and justify your answer. Figure 3 Van Deemter plots for hydroquinone using different column inner diameters (i.d. in μm). The data was obtained from liquid chromatography experiments using fused-silica capillary columns packed with 1.0-μm particles. 35 20 H(um) 큰 20 15 90 0+ 1500 100 75 550 01 02 594 05 μ(cm/sec) 30 15 10

Answer 2

Question

Chapter 14.2, Problem 14.4P

(a)

Interpretation Introduction

Interpretation:

Structure of an aldotetrose has to be drawn.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

(b)

Interpretation Introduction

Interpretation:

Structure of a ketopentose has to be drawn.

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

Structure of an aldohexose has to be drawn.

Concept Introduction:

Refer part (a).

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Answer 3

Question

Chapter 14.2, Problem 14.4P

(a)

Interpretation Introduction

Interpretation:

Structure of an aldotetrose has to be drawn.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

(b)

Interpretation Introduction

Interpretation:

Structure of a ketopentose has to be drawn.

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

Structure of an aldohexose has to be drawn.

Concept Introduction:

Refer part (a).

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Answer 4

Question

Chapter 14.2, Problem 14.4P

(a)

Interpretation Introduction

Interpretation:

Structure of an aldotetrose has to be drawn.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

(b)

Interpretation Introduction

Interpretation:

Structure of a ketopentose has to be drawn.

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

Structure of an aldohexose has to be drawn.

Concept Introduction:

Refer part (a).

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Answer 5

Chapter 14.2, Problem 14.4P

(a)

Interpretation Introduction

Interpretation:

Structure of an aldotetrose has to be drawn.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

(b)

Interpretation Introduction

Interpretation:

Structure of a ketopentose has to be drawn.

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

Structure of an aldohexose has to be drawn.

Concept Introduction:

Refer part (a).

Answer 6

Chapter 14.2, Problem 14.4P

(a)

Interpretation Introduction

Interpretation:

Structure of an aldotetrose has to be drawn.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

Answer 7

Chapter 14.2, Problem 14.4P

(a)

Interpretation Introduction

Interpretation:

Structure of an aldotetrose has to be drawn.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

Answer 8

(b)

Interpretation Introduction

Interpretation:

Structure of a ketopentose has to be drawn.

Concept Introduction:

Refer part (a).

Answer 9

(b)

Interpretation Introduction

Interpretation:

Structure of a ketopentose has to be drawn.

Concept Introduction:

Refer part (a).

Answer 10

(c)

Interpretation Introduction

Interpretation:

Structure of an aldohexose has to be drawn.

Concept Introduction:

Refer part (a).

Answer 11

(c)

Interpretation Introduction

Interpretation:

Structure of an aldohexose has to be drawn.

Concept Introduction:

Refer part (a).

Answer 12

Expert Solution & Answer

Answer 13

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Answer 14

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Answer 15

Ch. 14.1 - Draw a Lewis structure for glucose that clearly...Ch. 14.2 - Prob. 14.2P Ch. 14.2 - Prob. 14.3P Ch. 14.2 - Prob. 14.4P Ch. 14.2 - Rank the following compounds in order of...Ch. 14.2 - Prob. 14.6P Ch. 14.2 - Prob. 14.7P Ch. 14.2 - Prob. 14.8P Ch. 14.2 - Prob. 14.9P Ch. 14.3 - Prob. 14.10P

Solution Summary: The author explains that simplest carbohydrates are known as monosaccharides. They contain three to six carbons in a chain form, and have the carbonyl group at the terminal or the adjacent carbon atom from the

Concept explainers

Interpretation:

Structure of a ketopentose has to be drawn.

Concept Introduction:

Refer part (a).

Interpretation:

Structure of an aldohexose has to be drawn.

Concept Introduction:

Refer part (a).

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Chapter 14 Solutions

Solution Summary: The author explains that simplest carbohydrates are known as monosaccharides. They contain three to six carbons in a chain form, and have the carbonyl group at the terminal or the adjacent carbon atom from the

Concept explainers

Interpretation: Structure of a ketopentose has to be drawn. Concept Introduction: Refer part (a).

Interpretation: Structure of an aldohexose has to be drawn. Concept Introduction: Refer part (a).

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Chapter 14 Solutions

Interpretation:

Structure of a ketopentose has to be drawn.

Concept Introduction:

Refer part (a).

Interpretation:

Structure of an aldohexose has to be drawn.

Concept Introduction:

Refer part (a).