EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
3rd Edition
ISBN: 9781259298424
Author: SMITH
Publisher: VST
bartleby

Videos

Textbook Question
Book Icon
Chapter 14, Problem 14.42P

Give the IUAPC name for each alcohol.
Chapter 14, Problem 14.42P, Give the IUAPC name for each alcohol. , example  1
Chapter 14, Problem 14.42P, Give the IUAPC name for each alcohol. , example  2

Expert Solution
Check Mark
Interpretation Introduction

(a)

Interpretation:

The IUPAC name of the following compound should be determined:

  EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 14, Problem 14.42P , additional homework tip  1

Concept Introduction:

Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.

Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.

Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.

When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.

Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.

Answer to Problem 14.42P

6-methyl-3-heptanol.

Explanation of Solution

  C8H18O contains seven membered main carbon chain. Methyl group is connected to the main carbon chain from the 6th position and OH group is connected to the main carbon chain via 3rd position. Hence; IUPAC name for the C8H18O is 6-methyl-3-heptanol.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation:

The IUPAC name of the following compound should be determined:

  EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 14, Problem 14.42P , additional homework tip  2

Concept Introduction:

Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.

Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.

Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.

When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.

Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.

Answer to Problem 14.42P

2-ethylpentanol.

Explanation of Solution

( C7H16O ) contains five membered main carbon chain. Ethyl group is connected to the main carbon chain from the 2nd position and OH group is connected to the main carbon chain via 1st position. Hence; IUPAC name for the C7H16O is 2-ethylpentanol.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation:

The IUPAC name of the following compound should be determined:

  EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 14, Problem 14.42P , additional homework tip  3

Concept Introduction:

Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.

Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.

Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.

When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.

Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.

Answer to Problem 14.42P

3-methylheptanol.

Explanation of Solution

( C7H18O ) contains seven membered main carbon chain. Methyl group is connected to the main carbon chain from the 3rdposition and OH group is connected to the main carbon chain via 1st position. Hence; IUPAC name for the C7H18O is 3-methylheptanol.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation:

The IUPAC name of the following compound should be determined:

  EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 14, Problem 14.42P , additional homework tip  4

Concept Introduction:

Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.

Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.

Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.

When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.

Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.

Answer to Problem 14.42P

1,2,3-propantriol.

Explanation of Solution

( C3H8O3 ) contains three membered main carbon chain. Each carbon connects to a OH group and this C3H8O3 is a triolwhich means more than one OH group. -triol suffix is added to the end of the parent alcohol and numbers are added as a prefix to indicate the positions of the -OH groups. Hence; IUPAC name for the C3H8O3 is1,2,3-propanthriol.

Expert Solution
Check Mark
Interpretation Introduction

(e)

Interpretation:

The IUPAC name of the following compound should be determined:

  EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 14, Problem 14.42P , additional homework tip  5

Concept Introduction:

Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.

Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.

Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.

When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.

Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.

Answer to Problem 14.42P

1-ethyl-2-methylcyclopentanol.

Explanation of Solution

( C8H16O ) contains five membered main carbon ring and OH group is directly connected to the cylopentane ring. Ethyl group is connected to the cylopentane ring via 1st position and methyl group is connected via 2nd position. Numbering of the carbon ring is done according to the nomenclature rules. The ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.

Hence; IUPAC name of the ( C8H16O ) is 1-ethyl-2-methylcyclopentanol.

Expert Solution
Check Mark
Interpretation Introduction

(f)

Interpretation:

The IUPAC name of the following compound should be determined:

  EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 14, Problem 14.42P , additional homework tip  6

Concept Introduction:

Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.

Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.

Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.

When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.

Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.

Answer to Problem 14.42P

3,4-dimethylcyclohexanol.

Explanation of Solution

( C8H16O ) contains six membered main carbon ring and OH group is directly connected to the cylohexane ring. Methyl groups are connected to the cyclohexane ring through 3rd and 4th positions. Numbering of the carbon ring is done according to the nomenclature rules. The ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.

Hence; IUPAC name of the ( C8H16O ) is 3,4-dimethylcyclohexanol.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
13 Consider the "C NMR spectrum below. 140 120 100 80 60 40 20 20 PPM 0 The spectrum belongs to which one of the following constitutional isomers of the compound C,H12? Select the single best answer. Check ✓ G Save For Later 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use
The structure of compound 1,3,5-trimethylbenzene (mesitylene) is given below. How many signals would you expect to find in the 'H NMR spectrum of 1,3,5-trimethylbenzene (mesitylene)? Check ×
1 How many signals do you expect in the 'H NMR spectrum for this molecule? CI CI Cl Write the answer in the table below. Also, in each of the drawing areas below is a copy of the molecule, with H atoms shown. In each copy, one of the H atoms is highlighted red. Highlight in red all other H atoms that would contribute to the same signal as the H already highlighted red. Note for advanced students: Remember, a multiplet is considered one signal in the 'H NMR spectrum. 1 Number of signals in the 'H NMR spectrum. ☐ For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. No additional H atoms to highlight in top molecule For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at…

Chapter 14 Solutions

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM

Ch. 14.5 - Prob. 14.11PCh. 14.6 - Prob. 14.12PCh. 14.6 - Prob. 14.13PCh. 14.7 - Prob. 14.14PCh. 14.7 - Prob. 14.15PCh. 14.7 - Prob. 14.16PCh. 14.7 - Prob. 14.17PCh. 14.8 - (a) Translate the hall and stick model of...Ch. 14.8 - Prob. 14.19PCh. 14.9 - Prob. 14.20PCh. 14.9 - Prob. 14.21PCh. 14.9 - Prob. 14.22PCh. 14.9 - Prob. 14.23PCh. 14.9 - Prob. 14.24PCh. 14.9 - Prob. 14.25PCh. 14.10 - Prob. 14.26PCh. 14.10 - Prob. 14.27PCh. 14.10 - Prob. 14.28PCh. 14 - Prob. 14.29PCh. 14 - Prob. 14.30PCh. 14 - Prob. 14.31PCh. 14 - Classify each halide hi A as 1°, 2°, or 3°. A is a...Ch. 14 - Prob. 14.33PCh. 14 - Draw the structure of a molecule that fits each...Ch. 14 - Draw the structure of the six constitutional...Ch. 14 - Draw the structure of the four constitutional...Ch. 14 - Prob. 14.37PCh. 14 - Prob. 14.38PCh. 14 - Prob. 14.39PCh. 14 - Answer each question about alcohol B. Draw a...Ch. 14 - Prob. 14.41PCh. 14 - Give the IUAPC name for each alcohol.Ch. 14 - Prob. 14.43PCh. 14 - Prob. 14.44PCh. 14 - Prob. 14.45PCh. 14 - Prob. 14.46PCh. 14 - Draw the structures and give the IUPAC names for...Ch. 14 - Prob. 14.48PCh. 14 - Prob. 14.49PCh. 14 - Prob. 14.50PCh. 14 - Give the structure corresponding to each IUPAC...Ch. 14 - Give the structure corresponding to each IUPAC...Ch. 14 - Which compound in each pair has the higher boiling...Ch. 14 - Rank the compounds in order of increasing melting...Ch. 14 - Rank the following compounds in order of...Ch. 14 - Rank the following compounds in order of...Ch. 14 - Prob. 14.57PCh. 14 - Prob. 14.58PCh. 14 - Prob. 14.59PCh. 14 - Prob. 14.60PCh. 14 - Prob. 14.61PCh. 14 - Prob. 14.62PCh. 14 - Prob. 14.63PCh. 14 - Prob. 14.64PCh. 14 - Prob. 14.65PCh. 14 - Prob. 14.66PCh. 14 - Prob. 14.67PCh. 14 - Prob. 14.68PCh. 14 - Prob. 14.69PCh. 14 - Prob. 14.70PCh. 14 - Prob. 14.71PCh. 14 - Prob. 14.72PCh. 14 - Prob. 14.73PCh. 14 - Prob. 14.74PCh. 14 - Prob. 14.75PCh. 14 - Prob. 14.76PCh. 14 - Prob. 14.77PCh. 14 - Prob. 14.78PCh. 14 - Prob. 14.79PCh. 14 - Prob. 14.80PCh. 14 - Prob. 14.81PCh. 14 - Prob. 14.82PCh. 14 - Prob. 14.83PCh. 14 - Prob. 14.84PCh. 14 - Prob. 14.85PCh. 14 - Prob. 14.86PCh. 14 - With reference to the halogenated organic...Ch. 14 - Prob. 14.88PCh. 14 - Prob. 14.89PCh. 14 - Prob. 14.90PCh. 14 - Write out the chemical reaction that occurs when a...Ch. 14 - Prob. 14.92PCh. 14 - Prob. 14.93PCh. 14 - Lactic acid [CH3CH(OH)CO2H] gives sour milk its...Ch. 14 - Prob. 14.95PCh. 14 - Prob. 14.96PCh. 14 - Prob. 14.97PCh. 14 - Prob. 14.98PCh. 14 - Prob. 14.99PCh. 14 - Answer the following questions about alcohol B....Ch. 14 - Prob. 14.101CPCh. 14 - Dehydration of alcohol C forms two products of...
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
07 Physical Properties of Organic Compounds; Author: Mindset;https://www.youtube.com/watch?v=UjlSgwq4w6U;License: Standard YouTube License, CC-BY