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(a)
Interpretation:
The IUPAC name of the following compound should be determined:
Concept Introduction:
Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.
Longest carbon chain containing the carbon bonded to the OH group is named as an
Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.
When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.
Compounds which contains two OH groups are named as
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Answer to Problem 14.41P
2-pentanol.
Explanation of Solution
(b)
Interpretation:
The IUPAC name of the following compound should be determined:
Concept Introduction:
Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.
Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.
Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.
When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.
Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.
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Answer to Problem 14.41P
3,3-dimethyl-2-hexanol.
Explanation of Solution
(
(c)
Interpretation:
The IUPAC name of the following compound should be determined:
Concept Introduction:
Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.
Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.
Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.
When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.
Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.
![Check Mark](/static/check-mark.png)
Answer to Problem 14.41P
4-ethyl-6-methylheptanol.
Explanation of Solution
(
(d)
Interpretation:
The IUPAC name of the following compound should be determined:
Concept Introduction:
Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.
Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.
Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.
When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.
Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.
![Check Mark](/static/check-mark.png)
Answer to Problem 14.41P
4-butylcyclohexanol.
Explanation of Solution
(
Hence; IUPAC name of the (
(e)
Interpretation:
The IUPAC name of the following compound should be determined:
Concept Introduction:
Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.
Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.
Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.
When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.
Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.
![Check Mark](/static/check-mark.png)
Answer to Problem 14.41P
2,2-dimethylcyclobutanol.
Explanation of Solution
(
Hence; IUPAC name of the (
(f)
Interpretation:
The IUPAC name of the following compound should be determined:
Concept Introduction:
Alcohols are the organic molecules which have OH group bonded to a tetrahedral carbon atom.
Longest carbon chain containing the carbon bonded to the OH group is named as an alkane and -e of the alkane replaced by the suffix -ol.
Numbering of main carbon chain is done in such a way so that OH group gets the lowest number.
When OH group is bonded to a ring, the ring is numbered beginning with the OH group and the 1 is normally omitted from the name. The ring is numbered in clockwise or anticlockwise by giving the lowest number to the next substitute.
Compounds which contains two OH groups are named as diols and when in nomenclature, -diol suffix is added to the end of the parent alcohol and position of the OH groups are used as prefix to indicate the location of the two OH groups.
![Check Mark](/static/check-mark.png)
Answer to Problem 14.41P
2,5-diethylcyclopentanol.
Explanation of Solution
(
Hence; IUPAC name of the (
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Chapter 14 Solutions
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
- Nonearrow_forwardQ1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. + CI Br : Н OH H wo་ཡིག་ཐrow HO 3 D ။။ဂ CI Br H, CI Br Br H₂N OMe R IN I I N S H Br ជ័យ CI CI D OHarrow_forwardPlease correct answer and don't use hand ratingarrow_forward
- Nonearrow_forward%Reflectance 95 90- 85 22 00 89 60 55 50 70 65 75 80 50- 45 40 WA 35 30- 25 20- 4000 3500 Date: Thu Feb 06 17:21:21 2025 (GMT-05:0(UnknownD Scans: 8 Resolution: 2.000 3000 2500 Wavenumbers (cm-1) 100- 2981.77 1734.25 2000 1500 1000 1372.09 1108.01 2359.09 1469.82 1181.94 1145.20 1017.01 958.45 886.97 820.49 668.25 630.05 611.37arrow_forwardNonearrow_forward
- CH3 CH H3C CH3 H OH H3C- -OCH2CH3 H3C H -OCH3 For each of the above compounds, do the following: 1. List the wave numbers of all the IR bands in the 1350-4000 cm-1 region. For each one, state what bond or group it represents. 2. Label equivalent sets of protons with lower-case letters. Then, for each 1H NMR signal, give the 8 value, the type of splitting (singlet, doublet etc.), and the number protons it represents. of letter δ value splitting # of protons 3. Redraw the compound and label equivalent sets of carbons with lower-case letters. Then for each set of carbons give the 5 value and # of carbons it represents. letter δ value # of carbonsarrow_forwardDraw the correct ionic form(s) of arginine at the pKa and PI in your titration curve. Use your titration curve to help you determine which form(s) to draw out.arrow_forwardPlease correct answer and don't use hand ratingarrow_forward
- Nonearrow_forwardNonearrow_forwardCarbohydrates- Draw out the Hawthorne structure for a sugar from the list given in class. Make sure to write out all atoms except for carbons within the ring. Make sure that groups off the carbons in the ring are in the correct orientation above or below the plane. Make sure that bonds are in the correct orientation. Include the full name of the sugar. You can draw out your curve within the text box or upload a drawing below.arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
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