To Find:Measures of variation and any outliers for each set of data.
Answer to Problem 6PPS
Median=
Lower quartile =
Upper quartile =
Interquartile=
Outlier=
Explanation of Solution
Given: Find the measures of variation and any outliers for each set of data.
Highest vale =
Lowest value =
Range = Highest value − lowest value
For median:
Median
Then
Lower quartile =
Upper quartile =
Interquartile= Upper quartile − lower quartile
Multiply the interquartile range by
Subtract
Hence there is one outliers=
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