Chapter 13, Problem 41SGR

To determine

Calculate probability of P (green and then green) without replacement.

Answer to Problem 41SGR

Probability of finding green and then green without replacement is $\frac{10}{153}$

Explanation of Solution

Given:

No. of red marker=8

No. of green marker=5

No. of white marker = 5

Calculations:

Here, we have to calculate probability of finding blue white and again white marker in a box without any replacement.

Total number of markers =8+5+5=18

Probability of finding first green marker is,

  $P(firstgreen)=\frac{No.ofgreenmar\ker }{Totalno.ofmar\ker s}=\frac{5}{18}$

Probability of finding second white marker is,

  $P(\sec ondgreen)=\frac{No.ofgreenmar\ker afterremovingonegreenmar\ker }{Totalno.ofmar\ker afterremovingonegreenmar\ker }=\frac{4}{17}$

Probability of finding green and then green marker is

  $\begin{array}{l}P(greenandthengreen)=P(firstgreen)\times P(\sec ondgreen)\\ =\frac{5}{18}\times \frac{4}{17}\\ =\frac{20}{306}\\ =\frac{10}{153}\end{array}$

Conclusion:

Therefore, we are able to calculate probability of finding green and then green marker in a box.