Chapter 13.10, Problem 12PPS

To determine

The probability ofoutcome of candies.

P (two red candies)

Answer to Problem 12PPS

The probability of outcome of candiesis P (two red candies)= $\frac{1}{40}$

Explanation of Solution

Given:

Blue: $6$

Red: $3$

Green: $5$

Yellow: $2$

Total Candies: $6+3+5+2=16$

Calculation:

Fraction Form:

As calculate first red candy and then second red candy, in first red candy get the total number of red candy and total number of candies.

P (First candy is red) = $\frac{3}{16}$

In second red candy remove $1$ red candy from the total red candies and total number of candies, so

P (Second candy is red) = $\frac{2}{15}$

P (two red candies) = P (first) * P (second)

  $\begin{array}{l}=\frac{3}{16}\times \frac{2}{15}\\ =\left(\frac{3.2}{16.15}\right)\\ =\frac{6}{240}\\ =\frac{1}{40}\end{array}$

Conclusion:

Hence, P (two red candies)= $\frac{1}{40}$