EBK CHEMICAL PRINCIPLES
EBK CHEMICAL PRINCIPLES
8th Edition
ISBN: 9781305856745
Author: DECOSTE
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Chapter 13, Problem 85E

(a)

Interpretation Introduction

Interpretation: The Lewis structure for POCl3  that obeys the octet rule needs to be drawn.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that exist on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

Formal charge on each atom can be determined with the help of number of valence shell electrons, number of lone pair electrons and bond pair electrons. The formula for the formal charge can be written as:

  FC = VE – LE – bond pairFC= formal chargeVE = Valence electrons LE= number of lone pair electrons Bond pair = Number of bond pairs

(a)

Expert Solution
Check Mark

Answer to Problem 85E

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  1

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in POCl3 :

  (1×5)+(1×6)+(3×7)=32

Hence the best Lewis structure for POCl3 must be:

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  2

  FC = VE – LE – bond pairFC on P  = 5  - 0 -4 = +1FC on Cl  = 7  - 6 - 1 = 0FC on O  = 6  - 6 - 1 = -1

(b)

Interpretation Introduction

Interpretation: The Lewis structure for SO42-  that obeys the octet rule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that exist on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

Formal charge on each atom can be determined with the help of number of valence shell electrons, number of lone pair electrons and bond pair electrons. The formula for the formal charge can be written as:

  FC = VE – LE – bond pairFC= formal chargeVE = Valence electrons LE= number of lone pair electrons Bond pair = Number of bond pairs

(b)

Expert Solution
Check Mark

Answer to Problem 85E

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  3

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in SO42- :

  (1×6)+(4×6)+2=32

Hence the best Lewis structure for SO42- must be:

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  4

  FC = VE – LE – bond pairFC on S  = 6  - 0 - 4 = +2FC on O( -O)  = 6  - 6 - 1 = -1

(c)

Interpretation Introduction

Interpretation: The Lewis structure for ClO4- that obeys the octet rule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that exist on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

Formal charge on each atom can be determined with the help of number of valence shell electrons, number of lone pair electrons and bond pair electrons. The formula for the formal charge can be written as:

  FC = VE – LE – bond pairFC= formal chargeVE = Valence electrons LE= number of lone pair electrons Bond pair = Number of bond pairs

(c)

Expert Solution
Check Mark

Answer to Problem 85E

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  5

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in ClO4- :

  (1×7)+(4×6)+1=32

Hence the best Lewis structure for ClO4- must be:

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  6

  FC = VE – LE – bond pairFC on Cl  = 7 - 0 - 4 = +3FC on O( -O)  = 6  - 6 - 1 = -1

(d)

Interpretation Introduction

Interpretation: The Lewis structure for PO43- that obey the octet rule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that exist on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

Formal charge on each atom can be determined with the help of number of valence shell electrons, number of lone pair electrons and bond pair electrons. The formula for the formal charge can be written as:

  FC = VE – LE – bond pairFC= formal chargeVE = Valence electrons LE= number of lone pair electrons Bond pair = Number of bond pairs

(d)

Expert Solution
Check Mark

Answer to Problem 85E

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  7

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in PO43- :

  (1×5)+(4×6)+3=32

Hence the best Lewis structure for PO43- must be:

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  8

  FC = VE – LE – bond pairFC on P  = 5 - 0 - 4 = +1FC on O( -O)  = 6  - 6 - 1 = -1

(e)

Interpretation Introduction

Interpretation: The Lewis structure for SO2Cl2 that obeys the octet rule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that exist on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

Formal charge on each atom can be determined with the help of number of valence shell electrons, number of lone pair electrons and bond pair electrons. The formula for the formal charge can be written as:

  FC = VE – LE – bond pairFC= formal chargeVE = Valence electrons LE= number of lone pair electrons Bond pair = Number of bond pairs

(e)

Expert Solution
Check Mark

Answer to Problem 85E

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  9

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in SO2Cl2 :

  (1×6)+(2×6)+(2×7)=32

Hence the best Lewis structure for SO2Cl2 must be:

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  10

  FC = VE – LE – bond pairFC on S  = 6 - 0 - 4 = +2FC on Cl  = 7  - 6 - 1 = 0FC on O  = 6  - 6 - 1 = -1

(f)

Interpretation Introduction

Interpretation: The Lewis structure for XeO4 that obeys the octet rule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that exist on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

Formal charge on each atom can be determined with the help of number of valence shell electrons, number of lone pair electrons and bond pair electrons. The formula for the formal charge can be written as:

  FC = VE – LE – bond pairFC= formal chargeVE = Valence electrons LE= number of lone pair electrons Bond pair = Number of bond pairs

(f)

Expert Solution
Check Mark

Answer to Problem 85E

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  11

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in XeO4 :

  (1×8)+(4×6)=32

Hence the best Lewis structure for XeO4 must be:

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  12

  FC = VE – LE – bond pairFC on Xe  = 8 - 0 - 4 = +4FC on O  = 6  - 6 -1 =-1

(g)

Interpretation Introduction

Interpretation: The Lewis structure for  ClO3- that obeys the octet rule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that exist on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

Formal charge on each atom can be determined with the help of number of valence shell electrons, number of lone pair electrons and bond pair electrons. The formula for the formal charge can be written as:

  FC = VE – LE – bond pairFC= formal chargeVE = Valence electrons LE= number of lone pair electrons Bond pair = Number of bond pairs

(g)

Expert Solution
Check Mark

Answer to Problem 85E

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  13

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in ClO3- :

  (1×7)+(3×6)+1=26

Hence the best Lewis structure for ClO3- must be:

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  14

  FC = VE – LE – bond pairFC on Cl  = 7 - 2 - 4 = +1FC on O( -O)  = 6  - 6 - 1 = -1FC on O (=O)  = 6  - 4 - 2 = 0

(h)

Interpretation Introduction

Interpretation: The Lewis structure for NO43- that obeys the octet rule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that exist on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

Formal charge on each atom can be determined with the help of number of valence shell electrons, number of lone pair electrons and bond pair electrons. The formula for the formal charge can be written as:

  FC = VE – LE – bond pairFC= formal chargeVE = Valence electrons LE= number of lone pair electrons Bond pair = Number of bond pairs

(h)

Expert Solution
Check Mark

Answer to Problem 85E

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  15

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in NO43- :

  (1×5)+(4×6)+1=30

Hence the best Lewis structure for NO43- must be:

  EBK CHEMICAL PRINCIPLES, Chapter 13, Problem 85E , additional homework tip  16

  FC = VE – LE – bond pairFC on N  = 5 - 2 - 3 = 0FC on O( -O)  = 6  - 6 - 1 = -1FC on O (=O)  = 6  - 4 - 2 = 0

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Chapter 13 Solutions

EBK CHEMICAL PRINCIPLES

Ch. 13 - Prob. 11DQCh. 13 - Prob. 12DQCh. 13 - Prob. 13ECh. 13 - Prob. 14ECh. 13 - An alternative definition of electronegativity...Ch. 13 - Prob. 16ECh. 13 - Without using Fig. 13.3, predict the order of...Ch. 13 - Without using Fig. 13.3, predict which bond in...Ch. 13 - Prob. 19ECh. 13 - Prob. 20ECh. 13 - Indicate the bond polarity (show the partial...Ch. 13 - Prob. 22ECh. 13 - Prob. 23ECh. 13 - Prob. 24ECh. 13 - Prob. 25ECh. 13 - Prob. 26ECh. 13 - Prob. 27ECh. 13 - Prob. 28ECh. 13 - Prob. 29ECh. 13 - Prob. 30ECh. 13 - Prob. 31ECh. 13 - Give an example of an ionic compound where both...Ch. 13 - What noble gas has the same electron configuration...Ch. 13 - Which of the following ions have noble gas...Ch. 13 - Give three ions that are isoelectronic with...Ch. 13 - Prob. 36ECh. 13 - Predict the empirical formulas of the ionic...Ch. 13 - Which compound in each of the following pairs of...Ch. 13 - Use the following data to estimate Hf for...Ch. 13 - Use the following data to estimate Hf for...Ch. 13 - Consider the following:...Ch. 13 - In general, the higher the charge on the ions in...Ch. 13 - Consider the following energy changes: a....Ch. 13 - Prob. 44ECh. 13 - Prob. 45ECh. 13 - The lattice energies of FeCl3,FeCl2,andFe2O3 are...Ch. 13 - Prob. 47ECh. 13 - Prob. 48ECh. 13 - Prob. 49ECh. 13 - Prob. 50ECh. 13 - Prob. 51ECh. 13 - Prob. 52ECh. 13 - Prob. 53ECh. 13 - Prob. 54ECh. 13 - Prob. 55ECh. 13 - Prob. 56ECh. 13 - Prob. 57ECh. 13 - Prob. 58ECh. 13 - Prob. 59ECh. 13 - Prob. 60ECh. 13 - Prob. 61ECh. 13 - Prob. 62ECh. 13 - Prob. 63ECh. 13 - Prob. 64ECh. 13 - Prob. 65ECh. 13 - Prob. 66ECh. 13 - Prob. 67ECh. 13 - Prob. 68ECh. 13 - Prob. 69ECh. 13 - Prob. 70ECh. 13 - Prob. 71ECh. 13 - Prob. 72ECh. 13 - Prob. 73ECh. 13 - Prob. 74ECh. 13 - Prob. 75ECh. 13 - Prob. 76ECh. 13 - Prob. 77ECh. 13 - Prob. 78ECh. 13 - Prob. 79ECh. 13 - Prob. 80ECh. 13 - Prob. 81ECh. 13 - Prob. 82ECh. 13 - Prob. 83ECh. 13 - Prob. 84ECh. 13 - Prob. 85ECh. 13 - Prob. 86ECh. 13 - Prob. 87ECh. 13 - Prob. 88ECh. 13 - Prob. 89ECh. 13 - Prob. 90ECh. 13 - Prob. 91ECh. 13 - Prob. 92ECh. 13 - Prob. 93ECh. 13 - Prob. 94ECh. 13 - Prob. 95ECh. 13 - Predict the molecular structure and the bond...Ch. 13 - Prob. 97ECh. 13 - Two variations of the octahedral geometry are...Ch. 13 - Prob. 99ECh. 13 - Predict the molecular structure and the bond...Ch. 13 - Which of the molecules in Exercise 96 have net...Ch. 13 - Prob. 102ECh. 13 - Give two requirements that should be satisfied for...Ch. 13 - What do each of the following sets of...Ch. 13 - Prob. 105ECh. 13 - Consider the following Lewis structure, where E is...Ch. 13 - Consider the following Lewis structure, where E is...Ch. 13 - Prob. 108ECh. 13 - Prob. 109ECh. 13 - Which of the following molecules have net dipole...Ch. 13 - Prob. 111AECh. 13 - Prob. 112AECh. 13 - Prob. 113AECh. 13 - Prob. 114AECh. 13 - Prob. 115AECh. 13 - There are two possible structures of XeF2Cl2 ,...Ch. 13 - Prob. 117AECh. 13 - Prob. 118AECh. 13 - Prob. 119AECh. 13 - Prob. 120AECh. 13 - Prob. 121AECh. 13 - Prob. 122AECh. 13 - Prob. 123AECh. 13 - Prob. 124AECh. 13 - Prob. 125AECh. 13 - Prob. 126AECh. 13 - Prob. 127AECh. 13 - Prob. 128AECh. 13 - Prob. 129AECh. 13 - Prob. 130AECh. 13 - Prob. 131AECh. 13 - Prob. 132AECh. 13 - Prob. 133CPCh. 13 - Prob. 134CPCh. 13 - Given the following information: Heat of...Ch. 13 - Prob. 136CPCh. 13 - A promising new material with great potential as...Ch. 13 - Think of forming an ionic compound as three steps...Ch. 13 - Prob. 139CPCh. 13 - Prob. 140CPCh. 13 - Calculate the standard heat of formation of the...Ch. 13 - Prob. 142CPCh. 13 - Prob. 143MP
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