Themost stable ion from Na, Mg, Al, S, Cl, K, Ca and Ganeeds to be determined and the ions needs to be arranged from largest to smallest radius. Concept Introduction: A chemical compound can be formed by either ionic bond or covalent bond between bonded atoms. The ionic compound is formed by opposite charge ions; cations and anions. The covalent compound is formed by sharing of electrons between bonded atoms. Atoms always take the way which is easier or involves less number of electrons. Therefore the atom with 1, 2, 3 valence electrons usually tend to lose electrons and form cation whereas the atom with 4, 5, valence electrons usually share electrons to form covalent bond. The atoms with 6, 7 valence electrons tend to form anion by gain of electron.

Question

Want to see the full answer?

Answer 1

Question

Chapter 13, Problem 3DQ

Interpretation Introduction

Interpretation:Themost stable ion from Na, Mg, Al, S, Cl, K, Ca and Ganeeds to be determined and the ions needs to be arranged from largest to smallest radius.

Concept Introduction: A chemical compound can be formed by either ionic bond or covalent bond between bonded atoms. The ionic compound is formed by opposite charge ions; cations and anions. The covalent compound is formed by sharing of electrons between bonded atoms.

Atoms always take the way which is easier or involves less number of electrons. Therefore the atom with 1, 2, 3 valence electrons usually tend to lose electrons and form cation whereas the atom with 4, 5, valence electrons usually share electrons to form covalent bond. The atoms with 6, 7 valence electrons tend to form anion by gain of electron.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Part VII. The H-NMR of a compound with molecular formula C5 H 10 O2 is given below. Find the following: (a) The no. of protons corresponding to each signal in the spectra (6) Give the structure of the compound and assign the signals to each proton in the compound. a 70.2 Integration Values C5H10O2 b 47.7 C 46.5 d 69.5 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 Chemical Shift (ppm) 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8

Part 111. 1 H-NMR spectrum of a compound with integration values in red is given below. Answer the following: (a) write the signals in the 'H-NMR spectrum to the corresponding protons on the structure of the molecule below. (b) Identify the theoretical multiplicities for each proton in the compound. Also give the possible. complex splitting patterns assuming J values are not similar. там Br 22 2 3 6 4 7.2 7.0 6.8 6.6 6.4 6.2 6.0 5.8 5.6 5.4 5.2 5.0 4.8 4.6 4.4 4.2 4.0 3.8 3.6 3.4 3.2 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0 Chemical Shift (ppm) ra. Br 2 3 6 6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8 Chemical Shift (ppm) 2 2 Br 7.3 7.2 7.1 7.0 6.9 6.7 6.6 6.5 6.4 6.3 6.2 6.1 6.0 Chemical Shift (ppm) 5.9 5.8 5.7 5.5 5.4 5.3 5.2 5.0 4.9

1600° 1538°C 1493°C In the diagram, the letter L indicates that it is a liquid. Indicate its components in the upper region where only L is indicated. The iron-iron carbide phase diagram. Temperature (°C) 1400 8 1394°C y+L 1200 2.14 y, Austenite 10000 912°C 800a 0.76 0.022 600 400 (Fe) a, Ferrite Composition (at% C) 15 1147°C a + Fe3C 2 3 Composition (wt% C) L 2500 4.30 2000 y + Fe3C 727°C 1500 Cementite (Fe3C) 1000 4 5 6 6.70 Temperature (°F)