Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN: 9781337399425
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 13, Problem 34QAP
Interpretation Introduction

Interpretation:

Final temperature of gas should be determined.

Concept Introduction:

Charles’s law: It is also known as temperature volume relationship. It states that volume of given mass of gas is directly proportional to its temperature.

Expert Solution
Check Mark

Answer to Problem 34QAP

Final temperature of gas is 237.750C.

Explanation of Solution

Relation between volume and temperature is given by Charles’s law.

Charles’s law states that volume of given mass of gas is directly proportional to its temperature. As temperature increases volume also increases.

Mathematical expression is:

V1T1=V2T2=k at constant pressure

Initial volume of gas = 2.01×102L

Initial temperature of gas (T1) = 11500C = 273.15+1150=1423.15 K

Final volume of gas = 5L

Substituting the values in Charles’s equation,

V1T1=V2T2=k at constant pressure

2.01×1021423.15=5T2

T2=35.4K

Can be converted into Celsius

Celcius+273.15=Kelvin

Kelvin = 35-273.15=237.750C.

Interpretation Introduction

Interpretation:

Final volume of gas should be determined.

Concept Introduction:

Charles’s law: It is also known as temperature volume relationship. It states that volume of given mass of gas is directly proportional to its temperature.

Expert Solution
Check Mark

Answer to Problem 34QAP

Final volume of gas is 0 mL.

Explanation of Solution

Relation between volume and temperature is given by Charles’s law.

Charles’s law states that volume of given mass of gas is directly proportional to its temperature. As temperature increases volume also increases.

Mathematical expression is:

V1T1=V2T2=k at constant pressure

Initial volume of gas = 44.2mL

Initial temperature of gas (T1) = 298K

Final volume of gas = ?

Final Temperature of gas (T2)=0K

Substituting the values in Charles’s equation,

V1T1=V2T2=k at constant pressure

44.2298=V20V2=0mL.

Interpretation Introduction

Interpretation:

Final volume of gas should be determined.

Concept Introduction:

Charles’s law: It is also known as temperature volume relationship. It states that volume of given mass of gas is directly proportional to its temperature.

Expert Solution
Check Mark

Answer to Problem 34QAP

Final volume of gas is 40.51mL.

Explanation of Solution

Relation between volume and temperature is given by Charles’s law.

Charles’s law states that volume of given mass of gas is directly proportional to its temperature. As temperature increases volume also increases.

Mathematical expression is:

V1T1=V2T2=k at constant pressure

Initial volume of gas = 44.2mL

Initial temperature of gas (T1) = 298K

Final volume of gas = ?

Final Temperature of gas (T2)= 00C = 0+273.15=273.15K

Substituting the values in Charles’s equation,

V1T1=V2T2=k at constant pressure

44.2298=V2273.15

V2=40.51mL.

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Chapter 13 Solutions

Introductory Chemistry: A Foundation

Ch. 13.6 - Prob. 13.10SCCh. 13.8 - Prob. 1CTCh. 13.10 - trong>Exercise 13.11 Calculate the volume of...Ch. 13.10 - at if STP was defined as normal room temperature...Ch. 13.10 - Prob. 13.12SCCh. 13 - Prob. 1ALQCh. 13 - Prob. 2ALQCh. 13 - Prob. 3ALQCh. 13 - Prob. 4ALQCh. 13 - Prob. 5ALQCh. 13 - Prob. 6ALQCh. 13 - Prob. 7ALQCh. 13 - Prob. 8ALQCh. 13 - Prob. 9ALQCh. 13 - Prob. 10ALQCh. 13 - Prob. 11ALQCh. 13 - Prob. 12ALQCh. 13 - Prob. 13ALQCh. 13 - Draw molecular—level views than show the...Ch. 13 - Prob. 15ALQCh. 13 - Prob. 16ALQCh. 13 - Prob. 17ALQCh. 13 - Prob. 18ALQCh. 13 - Prob. 19ALQCh. 13 - Prob. 20ALQCh. 13 - You are holding two balloons of the same volume....Ch. 13 - Prob. 22ALQCh. 13 - Prob. 23ALQCh. 13 - The introduction to this chapter says that "we...Ch. 13 - Prob. 2QAPCh. 13 - Prob. 3QAPCh. 13 - Prob. 4QAPCh. 13 - Prob. 5QAPCh. 13 - Prob. 6QAPCh. 13 - Prob. 7QAPCh. 13 - Prob. 8QAPCh. 13 - Prob. 9QAPCh. 13 - Prob. 10QAPCh. 13 - Make the indicated pressure conversions....Ch. 13 - Prob. 12QAPCh. 13 - Prob. 13QAPCh. 13 - Prob. 14QAPCh. 13 - Prob. 15QAPCh. 13 - Prob. 16QAPCh. 13 - Prob. 17QAPCh. 13 - Prob. 18QAPCh. 13 - Prob. 19QAPCh. 13 - Prob. 20QAPCh. 13 - Prob. 21QAPCh. 13 - Prob. 22QAPCh. 13 - 3. A sample of helium gas with a volume of...Ch. 13 - Prob. 24QAPCh. 13 - Prob. 25QAPCh. 13 - Prob. 26QAPCh. 13 - Prob. 27QAPCh. 13 - Prob. 28QAPCh. 13 - A sample of gas in a balloon has an initial...Ch. 13 - Suppose a 375mLsample of neon gas at 78Cis cooled...Ch. 13 - For each of the following sets of...Ch. 13 - For each of the following sets of...Ch. 13 - Prob. 33QAPCh. 13 - Prob. 34QAPCh. 13 - Suppose 1.25Lof argon is cooled from 291Kto 78K....Ch. 13 - Suppose a 125mLsample of argon is cooled from...Ch. 13 - Prob. 37QAPCh. 13 - Prob. 38QAPCh. 13 - Prob. 39QAPCh. 13 - Prob. 40QAPCh. 13 - Prob. 41QAPCh. 13 - If :math>1.04gof chlorine gas occupies a volume of...Ch. 13 - If 3.25moles of argon gas occupies a volume of...Ch. 13 - Prob. 44QAPCh. 13 - Prob. 45QAPCh. 13 - Prob. 46QAPCh. 13 - Prob. 47QAPCh. 13 - Prob. 48QAPCh. 13 - Prob. 49QAPCh. 13 - Prob. 50QAPCh. 13 - Prob. 51QAPCh. 13 - Determine the pressure in a 125Ltank containing...Ch. 13 - Prob. 53QAPCh. 13 - Prob. 54QAPCh. 13 - Prob. 55QAPCh. 13 - Suppose that a 1.25gsample of neon gas is confined...Ch. 13 - At what temperature will a 1.0gsample of neon gas...Ch. 13 - Prob. 58QAPCh. 13 - What pressure exists in a 200Ltank containing...Ch. 13 - Prob. 60QAPCh. 13 - Suppose a 24.3mLsample of helium gas at 25Cand...Ch. 13 - Prob. 62QAPCh. 13 - Prob. 63QAPCh. 13 - Prob. 64QAPCh. 13 - Prob. 65QAPCh. 13 - Prob. 66QAPCh. 13 - Prob. 67QAPCh. 13 - Suppose than 1.28gof neon gas and 2.49gof argon...Ch. 13 - A tank contains a mixture of 52.5gof oxygen gas...Ch. 13 - What mass of new gas would but required to fill a...Ch. 13 - Prob. 71QAPCh. 13 - Prob. 72QAPCh. 13 - A 500mLsample of O2gas at 24Cwas prepared by...Ch. 13 - Prob. 74QAPCh. 13 - Prob. 75QAPCh. 13 - Prob. 76QAPCh. 13 - Prob. 77QAPCh. 13 - Prob. 78QAPCh. 13 - Prob. 79QAPCh. 13 - Prob. 80QAPCh. 13 - Prob. 81QAPCh. 13 - Prob. 82QAPCh. 13 - Prob. 83QAPCh. 13 - Prob. 84QAPCh. 13 - Calcium oxide can be used to “scrub" carbon...Ch. 13 - Consider the following reaction:...Ch. 13 - Consider the following reaction for the combustion...Ch. 13 - Although we: generally think of combustion...Ch. 13 - m>89. Ammonia and gaseous hydrogen chloride...Ch. 13 - Calcium carbide, CaC2, reacts with water to...Ch. 13 - Prob. 91QAPCh. 13 - Prob. 92QAPCh. 13 - What volume does a mixture of 14.2gof He and...Ch. 13 - Prob. 94QAPCh. 13 - Prob. 95QAPCh. 13 - Consider the following chemical equation:...Ch. 13 - Prob. 97QAPCh. 13 - Dinitrogen monoxide, N2O, reacts with propane,...Ch. 13 - Consider the following unbalanced chemical...Ch. 13 - Prob. 100QAPCh. 13 - Prob. 101QAPCh. 13 - Prob. 102QAPCh. 13 - Prob. 103APCh. 13 - Prob. 104APCh. 13 - Prob. 105APCh. 13 - onsider the flasks in the following diagrams. mg...Ch. 13 - Prob. 107APCh. 13 - helium tank contains 25.2Lof helium m 8.40atm...Ch. 13 - Prob. 109APCh. 13 - Prob. 110APCh. 13 - Prob. 111APCh. 13 - Prob. 112APCh. 13 - Prob. 113APCh. 13 - Prob. 114APCh. 13 - Prob. 115APCh. 13 - Prob. 116APCh. 13 - Prob. 117APCh. 13 - 2.50Lcontainer at 1.00atm and 48Cis filled with...Ch. 13 - Prob. 119APCh. 13 - Prob. 120APCh. 13 - Prob. 121APCh. 13 - Prob. 122APCh. 13 - Prob. 123APCh. 13 - f a gaseous mixture is made of 3.50gof He and...Ch. 13 - Prob. 125APCh. 13 - Prob. 126APCh. 13 - f 5.l2gof oxygen gas occupies a volume of 6.21Lat...Ch. 13 - Prob. 128APCh. 13 - Prob. 129APCh. 13 - Prob. 130APCh. 13 - Prob. 131APCh. 13 - Prob. 132APCh. 13 - t what temperature does 4.00gof helium gas have a...Ch. 13 - Prob. 134APCh. 13 - f 3.20gof nitrogen gas occupies a volume of...Ch. 13 - Prob. 136APCh. 13 - mixture at 33Ccontains H2at 325torr, N2at 475torr,...Ch. 13 - Prob. 138APCh. 13 - Prob. 139APCh. 13 - he following demonstration takes place in a...Ch. 13 - onsider the following unbalanced chemical...Ch. 13 - Prob. 142APCh. 13 - Prob. 143APCh. 13 - Prob. 144APCh. 13 - Prob. 145APCh. 13 - Prob. 146APCh. 13 - Prob. 147APCh. 13 - Prob. 148APCh. 13 - Prob. 149APCh. 13 - omplete the following table for an ideal gas. mg...Ch. 13 - Prob. 151CPCh. 13 - Prob. 152CPCh. 13 - certain flexible weather balloon contains helium...Ch. 13 - Prob. 154CPCh. 13 - Prob. 155CPCh. 13 - Prob. 156CPCh. 13 - Prob. 157CP
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