A t = 5-mm -thick sheet of anodized aluminum is used to reject heat in a space power application. The edge of the sheet is attached to a hot source, and the sheet is maintained at nearly isothermal conditions at T = 300 K . The sheet is not subjected to irradiation. (a) Determine the ne radiation heat transfer from both sides of the 200 mm × 200 mm sheet to deep space. (b) An engineer suggests boring 3-mm-diameter holes through the sheet. The holes are spaced 5 mm apart. The interior surfaces of the holes are anodized after they are bored. Determine the net radiation heat transfer from both sides of the sheet to deep space. (c) As an alternative design, the 3-mm-diameter flat-bottomed holes are not bored completely through the sheet but are bored to depths of 2 mm on each side, leaving a 1-mm-thick web of aluminum separating the bottoms of the holes located on opposite sides of the sheet. Determine the net radiation heat transfer from both sides of the sheet to deep space. (d) Compare the ratio of the net radiation heat transfer to the mass of the sheet for the three designs.
A t = 5-mm -thick sheet of anodized aluminum is used to reject heat in a space power application. The edge of the sheet is attached to a hot source, and the sheet is maintained at nearly isothermal conditions at T = 300 K . The sheet is not subjected to irradiation. (a) Determine the ne radiation heat transfer from both sides of the 200 mm × 200 mm sheet to deep space. (b) An engineer suggests boring 3-mm-diameter holes through the sheet. The holes are spaced 5 mm apart. The interior surfaces of the holes are anodized after they are bored. Determine the net radiation heat transfer from both sides of the sheet to deep space. (c) As an alternative design, the 3-mm-diameter flat-bottomed holes are not bored completely through the sheet but are bored to depths of 2 mm on each side, leaving a 1-mm-thick web of aluminum separating the bottoms of the holes located on opposite sides of the sheet. Determine the net radiation heat transfer from both sides of the sheet to deep space. (d) Compare the ratio of the net radiation heat transfer to the mass of the sheet for the three designs.
Solution Summary: The author analyzes the net radiation heat transfer from both sides of the 200mmtimes sheet to deep space. The emissivity of anodized aluminum is eps
A
t
=
5-mm
-thick sheet of anodized aluminum is used to reject heat in a space power application. The edge of the sheet is attached to a hot source, and the sheet is maintained at nearly isothermal conditions at
T
=
300
K
. The sheet is not subjected to irradiation. (a) Determine the ne radiation heat transfer from both sides of the
200
mm
×
200
mm
sheet to deep space. (b) An engineer suggests boring 3-mm-diameter holes through the sheet. The holes are spaced 5 mm apart. The interior surfaces of the holes are anodized after they are bored. Determine the net radiation heat transfer from both sides of the sheet to deep space. (c) As an alternative design, the 3-mm-diameter flat-bottomed holes are not bored completely through the sheet but are bored to depths of 2 mm on each side, leaving a 1-mm-thick web of aluminum separating the bottoms of the holes located on opposite sides of the sheet. Determine the net radiation heat transfer from both sides of the sheet to deep space. (d) Compare the ratio of the net radiation heat transfer to the mass of the sheet for the three designs.
Consider the heat engine operating at steady state between the two thermal reservoirs shown at the right while producing a net power output of 700 kW. If 1000 kW of heat (Q̇H) is transferred to the heat engine from a thermal reservoir at a temperature of TH = 900 K, and heat is rejected to a thermal reservoir at a temperature of TL = 300 K, is this heat engine possible?
Can you answer this question for me and show all of the work
1.12 A disk of constant radius r is attached to a telescoping rod that is
extending at a constant rate as shown in Fig. P1.12. Both the disk
and the rod are rotating at a constant rate. Find the inertial
velocity and acceleration of point P at the rim of the disk.
ท2
L
0
SS
P
α
e
0
O'
êL
Fig. P1.12 Rotating disk attached to telescoping rod.
60 LL
Two different options A and B with brake pads for disc brakes are connected to the rope drum. The diameter of the rope drum is 150 mm. What distance must the pads B be at from the center of rotation to cover the same distance as A?A B- Width 50 mm - Width 60 mm- Evidence center 120mm - Construction power 900 N from rotation center.- Maintains a weight of 200 kgwhen the installation force is 1.4kN
(μ is missing from the data)M=μF(Ry-Ri)Right answer R=187 mm
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