A double-glazed window consists of two panes of glass, each of thickness t = 6 mm . The inside room temperature is T i = 20 ° C with h i = 7.7 W/m 2 ⋅ K , while the outside temperature is T o = − 10 ° C with h o = 25 W/m 2 ⋅ K . The gap between the glass sheets is of thickness L = 5 mm and is filled with a gas. The glass surfaces may be treated with a low-emissivity coating to reduce their emissivity from ε = 0.95 to ε = 0.05 . Determine the heat flux through the window for case ε 1 = ε 2 = 0.95 , case 2: ε 1 = ε 2 = 0.05 , and case 3: ε 1 = 0.05 , ε 2 = 0.95 . Consider either air or argon of thermal conductivity k Ar = 17.7 × 10 − 3 W/m ⋅ K to be within the gap. Radiation heat transfer occurring at the external surfaces of the two glass sheets is negligible, as is free convection between the glass sheets.
A double-glazed window consists of two panes of glass, each of thickness t = 6 mm . The inside room temperature is T i = 20 ° C with h i = 7.7 W/m 2 ⋅ K , while the outside temperature is T o = − 10 ° C with h o = 25 W/m 2 ⋅ K . The gap between the glass sheets is of thickness L = 5 mm and is filled with a gas. The glass surfaces may be treated with a low-emissivity coating to reduce their emissivity from ε = 0.95 to ε = 0.05 . Determine the heat flux through the window for case ε 1 = ε 2 = 0.95 , case 2: ε 1 = ε 2 = 0.05 , and case 3: ε 1 = 0.05 , ε 2 = 0.95 . Consider either air or argon of thermal conductivity k Ar = 17.7 × 10 − 3 W/m ⋅ K to be within the gap. Radiation heat transfer occurring at the external surfaces of the two glass sheets is negligible, as is free convection between the glass sheets.
Solution Summary: The author describes the heat flux through the window for the various cases. The length of windows is L=5mm.
A double-glazed window consists of two panes of glass, each of thickness
t
=
6
mm
. The inside room temperature is
T
i
=
20
°
C
with
h
i
=
7.7
W/m
2
⋅
K
, while the outside temperature is
T
o
=
−
10
°
C
with
h
o
=
25
W/m
2
⋅
K
. The gap between the glass sheets is of thickness
L
=
5
mm
and is filled with a gas. The glass surfaces may be treated with a low-emissivity coating to reduce their emissivity from
ε
=
0.95
to
ε
=
0.05
. Determine the heat flux through the window for case
ε
1
=
ε
2
=
0.95
, case 2:
ε
1
=
ε
2
=
0.05
, and case 3:
ε
1
=
0.05
,
ε
2
=
0.95
. Consider either air or argon of thermal conductivity
k
Ar
=
17.7
×
10
−
3
W/m
⋅
K
to be within the gap. Radiation heat transfer occurring at the external surfaces of the two glass sheets is negligible, as is free convection between the glass sheets.
Both portions of the rod ABC are made of an aluminum for which E = 70 GPa.
Based on the given information find:
1- deformation at A
2- stress in BC
3- Total strain
4- If v (Poisson ratio is 0.25, find the
lateral deformation of AB
Last 3 student ID+ 300 mm=L2
724
A
P=Last 2 student ID+ 300 KN
24
24
Diameter Last 2 student ID+ 15 mm
Last 3 student ID+ 500 mm=L1
724
C
B
24
Q=Last 2 student ID+ 100 KN
24
Diameter Last 2 student ID+ 40 mm
Q2Two wooden members of uniform cross section are joined by the simple scarf splice shown. Knowing that the
maximum allowable tensile stress in the glued splice is 75 psi, determine (a) the largest load P that can be safely
supported, (b) the corresponding shearing stress in the splice.
น
Last 1 student ID+5 inch=W
=9
4
L=Last 1 student ID+8 inch
=12
60°
P'
Q4
The two solid shafts are connected by gears as shown and are made of a steel for which the allowable shearing
stress is 7000 psi. Knowing the diameters of the two shafts are, respectively, dBC
determine the largest torque Tc that can be applied at C.
4
and dEF
dBC=Last 1 student ID+3 inch
dEF=Last 1 student ID+1 inch
7
R=Last 1 Student ID+5 inch
9
R
B
Tc
2.5 in.
E
TF
H
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