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Concept explainers
(a)
Interpretation:
The spatial arrangement for the
Concept Introduction:
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and
Saturated hydrocarbons are
Alkane has general molecular formula as
Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry. The carbon atoms that have only single bonds attached to it will have tetrahedral geometry. The carbon atoms that have a triple bond attached to it will have a linear geometry.
(a)
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Answer to Problem 13.38EP
The spatial arrangement is identified as tetrahedral.
Explanation of Solution
Given structure is,
Looking into the left most carbon atom present in the given structure, it is not bonded to any double bonds or triple bond. This carbon atom has only four single bonds (three with hydrogen and one with carbon atom). Therefore, the spatial arrangement of the left-most carbon atom is tetrahedral.
The spatial arrangement of the left-most carbon atom is identified.
(b)
Interpretation:
The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.
Concept Introduction:
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Saturated hydrocarbons are alkanes. Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.
Alkane has general molecular formula as
Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry. The carbon atoms that have only single bonds attached to it will have tetrahedral geometry. The carbon atoms that have a triple bond attached to it will have a linear geometry.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 13.38EP
The spatial arrangement is identified as tetrahedral.
Explanation of Solution
Given structure is,
Looking into the left most carbon atom present in the given structure, it is not bonded to any double bonds or triple bond. This carbon atom has only four single bonds (three with hydrogen and one with carbon atom). Therefore, the spatial arrangement of the left-most carbon atom is tetrahedral.
The spatial arrangement of the left-most carbon atom is identified.
(c)
Interpretation:
The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.
Concept Introduction:
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Saturated hydrocarbons are alkanes. Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.
Alkane has general molecular formula as
Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry. The carbon atoms that have only single bonds attached to it will have tetrahedral geometry. The carbon atoms that have a triple bond attached to it will have a linear geometry.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 13.38EP
The spatial arrangement is identified as trigonal planar.
Explanation of Solution
Given structure is,
Looking into the left most carbon atom present in the given structure, it is bonded to one double bond. This carbon atom has only two single bonds with hydrogen and a double bond with carbon atom. Therefore, the spatial arrangement of the left-most carbon atom is trigonal planar.
The spatial arrangement of the left-most carbon atom is identified.
(d)
Interpretation:
The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.
Concept Introduction:
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Saturated hydrocarbons are alkanes. Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.
Alkane has general molecular formula as
Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry. The carbon atoms that have only single bonds attached to it will have tetrahedral geometry. The carbon atoms that have a triple bond attached to it will have a linear geometry.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 13.38EP
The spatial arrangement is identified as tetrahedral.
Explanation of Solution
Given structure is,
Looking into the left most carbon atom present in the given structure, it is not bonded to any double bonds or triple bond. This carbon atom has only four single bonds (three with hydrogen and one with carbon atom). Therefore, the spatial arrangement of the left-most carbon atom is tetrahedral.
The spatial arrangement of the left-most carbon atom is identified.
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Chapter 13 Solutions
GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP
- Q1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. + CI Br : Н OH H wo་ཡིག་ཐrow HO 3 D ။။ဂ CI Br H, CI Br Br H₂N OMe R IN I I N S H Br ជ័យ CI CI D OHarrow_forwardPlease correct answer and don't use hand ratingarrow_forwardNonearrow_forward
- %Reflectance 95 90- 85 22 00 89 60 55 50 70 65 75 80 50- 45 40 WA 35 30- 25 20- 4000 3500 Date: Thu Feb 06 17:21:21 2025 (GMT-05:0(UnknownD Scans: 8 Resolution: 2.000 3000 2500 Wavenumbers (cm-1) 100- 2981.77 1734.25 2000 1500 1000 1372.09 1108.01 2359.09 1469.82 1181.94 1145.20 1017.01 958.45 886.97 820.49 668.25 630.05 611.37arrow_forwardNonearrow_forwardCH3 CH H3C CH3 H OH H3C- -OCH2CH3 H3C H -OCH3 For each of the above compounds, do the following: 1. List the wave numbers of all the IR bands in the 1350-4000 cm-1 region. For each one, state what bond or group it represents. 2. Label equivalent sets of protons with lower-case letters. Then, for each 1H NMR signal, give the 8 value, the type of splitting (singlet, doublet etc.), and the number protons it represents. of letter δ value splitting # of protons 3. Redraw the compound and label equivalent sets of carbons with lower-case letters. Then for each set of carbons give the 5 value and # of carbons it represents. letter δ value # of carbonsarrow_forward
- Nonearrow_forwardCarbohydrates- Draw out the Hawthorne structure for a sugar from the list given in class. Make sure to write out all atoms except for carbons within the ring. Make sure that groups off the carbons in the ring are in the correct orientation above or below the plane. Make sure that bonds are in the correct orientation. Include the full name of the sugar. You can draw out your curve within the text box or upload a drawing below.arrow_forwardHow many milliliters of 97.5(±0.5) wt% H2SO4 with a density of 1.84(±0.01) g/mL will you need to prepare 2.000 L of 0.110 M H2SO4? If the uncertainty in delivering H2SO4 is ±0.01 mL, calculate the absolute uncertainty in the molarity (0.110 M). Assume there is negligible uncertainty in the formula mass of H2SO4 and in the final volume (2.000 L) and assume random error.arrow_forward
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