
Concept explainers
(a)
Interpretation:
The molecular formula for the given compound has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and
(a)

Answer to Problem 13.33EP
Molecular formula of the compound is
Explanation of Solution
Given structure is,
Carbon atoms are present at the intersection and at the end points. The above structure has six intersections and two end points. Therefore, there is a total of eight carbon atoms. The given compound is found to have one double bond in it. The molecular formula for the given compound can be found by substituting in the general molecular formula of alkene that contain a single double bond as shown below,
The molecular formula of the given compound is identified as
The molecular formula for the given structure is identified.
(b)
Interpretation:
The molecular formula for the given compound has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Alkanes are a class of saturated hydrocarbons that do not contain a ring of carbon atoms but a chain of carbon atoms with carbon‑carbon single bonds. The general molecular formula for alkanes is
Alkenes and cycloalkenes are a class of unsaturated hydrocarbons that contain at least one double bond in its structure. The general molecular formula for alkene with one double bond is
(b)

Answer to Problem 13.33EP
Molecular formula of the compound is
Explanation of Solution
Given structure is,
Carbon atoms are present at the intersection and at the end points. The above structure has six intersections and two end points. Therefore, there is a total of eight carbon atoms. The given compound is found to have one double bond in it. The molecular formula for the given compound can be found by substituting in the general molecular formula of alkene that contain a single double bond as shown below,
The molecular formula of the given compound is identified as
The molecular formula for the given structure is identified.
(c)
Interpretation:
The molecular formula for the given compound has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Alkanes are a class of saturated hydrocarbons that do not contain a ring of carbon atoms but a chain of carbon atoms with carbon‑carbon single bonds. The general molecular formula for alkanes is
Alkenes and cycloalkenes are a class of unsaturated hydrocarbons that contain at least one double bond in its structure. The general molecular formula for alkene with one double bond is
(c)

Answer to Problem 13.33EP
Molecular formula of the compound is
Explanation of Solution
Given structure is,
Carbon atoms are present at the intersection and at the end points. The above structure has six intersections and two end points. Therefore, there is a total of eight carbon atoms. The given compound is found to have two double bonds in it. The molecular formula for the given compound can be found by substituting in the general molecular formula of alkene that contain two double bonds as shown below,
The molecular formula of the given compound is identified as
The molecular formula for the given structure is identified.
(d)
Interpretation:
The molecular formula for the given compound has to be identified.
Concept Introduction:
Organic compounds are the important basis of life. They include gasoline, coal, dyes, and clothing fibers etc. The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds. Organic compounds are found in earth also apart from living organisms. All the organic compounds contain the element carbon. Urea was synthesized in the laboratory which is an organic compound.
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Alkanes are a class of saturated hydrocarbons that do not contain a ring of carbon atoms but a chain of carbon atoms with carbon‑carbon single bonds. The general molecular formula for alkanes is
Alkenes and cycloalkenes are a class of unsaturated hydrocarbons that contain at least one double bond in its structure. The general molecular formula for alkene with one double bond is
(d)

Answer to Problem 13.33EP
Molecular formula of the compound is
Explanation of Solution
Given structure is,
Carbon atoms are present at the intersection and at the end points. The above structure has six intersections and four end points. Therefore, there is a total of ten carbon atoms. The given compound is found to have two double bonds in it. The molecular formula for the given compound can be found by substituting in the general molecular formula of alkene that contain two double bonds as shown below,
The molecular formula of the given compound is identified as
The molecular formula for the given structure is identified.
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Chapter 13 Solutions
GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP
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- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
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- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
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