
(a)
Interpretation: The major product of the given reaction has to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
(b)
Interpretation: The major product of the given reaction has to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
(c)
Interpretation: The major product of the given reaction has to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
Major product in the reaction of
General scheme:
It can be observed that the direct addition product has been formed from the direct reaction of the strong base with the carbonyl
The examples for the strong bases are:
(d)
Interpretation: The major product of the given reaction has to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
Major product in the reaction of
General scheme:
It can be observed that the direct addition product has been formed from the direct reaction of the strong base with the carbonyl functional group of the
The examples for the strong bases are:

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Chapter 12 Solutions
Essential Organic Chemistry (3rd Edition)
- no Ai walkthroughsarrow_forward136 PRACTICAL SPECTROSCOPY Compound 78 is a high-boiling liquid (boiling point 189° C) that contains halogen, but will not react with alkoxides to yield an halogen. ether. The Mass, IR, and 'H NMR spectra, along with 13C NMR data, are given below. Elemental Analysis: C, 35.32; H, 2.47; contains BC Spectral Data: doublet, 137.4 ppm; doublet, 130.1 ppm; doublet, 127.4 ppm; singlet, 97.3 ppm Absorbance Mass Spectrum Intensity 77 77 204 M + 128 40 60 80 100 120 140 160 180 m/e 200 220 280 240 260 300 Infrared Spectrum Wave Number, cm -1 4000 3000 2500 2000 1500 1300 1200 1100 1000 900 800 700 3 6 7 8 9 10 12 13 15 Wavelength, microns 'H NMR wwwww 5 Structure: www ppm, & ©2000 Brooks/Cole Publishing Com-arrow_forwardno Ai walkthroughsarrow_forward
- 3. Synthesize the following synthon from the indicated starting material. i HO.arrow_forwardIdentifying the stereochemistry of natural Write the complete common (not IUPAC) name of each molecule below. Note: if a molecule is one of a pair of enantiomers, be sure you start its name with D- or L- so we know which enantiomer it is. molecule H O-C-CH2 H3N. HN N H C=O common name (not the IUPAC name) NH3 ☐ H3N H ☐ CH2 Xarrow_forward> Draw the structure of alanine at pH 1.2. Click and drag to start drawing a structure.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
