Concept explainers
(a)
Interpretation:
The two names have to be given for the given compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry).IUPAC name consists of three parts, namely Prefix, suffix and root word.
Prefix- Represents the substituent present in the molecule and its position in the root name.
Suffix- Denotes the presence of
Root word - Represents the longest continuous carbon skeleton of the organic molecule.
The given compound is an
The given compound is
(b)
Interpretation:
The two names have to be given for the given compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry).IUPAC name consists of three parts, namely Prefix, suffix and root word.
Prefix- Represents the substituent present in the molecule and its position in the root name.
Suffix- Denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc. To add suffix to name a compound, the suffix “-ane” in the parent alkane is replaced by the respective suffix, which corresponds to the functional group present in the given compound. For carboxylic acid, suffix “-oic” will be added, for alcohol, suffix “-ol” will be added and so on
Root word - Represents the longest continuous carbon skeleton of the organic molecule.
The given compound is an aldehyde (
The given compound is ketone (
(c)
Interpretation:
The two names have to be given for the given compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry).IUPAC name consists of three parts, namely Prefix, suffix and root word.
Prefix- Represents the substituent present in the molecule and its position in the root name.
Suffix- Denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc. To add suffix to name a compound, the suffix “-ane” in the parent alkane is replaced by the respective suffix, which corresponds to the functional group present in the given compound. For carboxylic acid, suffix “-oic” will be added, for alcohol, suffix “-ol” will be added and so on
Root word - Represents the longest continuous carbon skeleton of the organic molecule.
The given compound is an aldehyde (
The given compound is ketone (
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Chapter 12 Solutions
Pearson eText for Essential Organic Chemistry -- Instant Access (Pearson+)
- Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the structure of the missing reactants, intermediates, or products in the following mechanism. Include all lone pairs. Ignore stereochemistry. Ignore inorganic byproducts. H Br2 (1 equiv) H- Select to Draw Starting Alkene Draw Major Product I I H2O 四: ⑦.. Q Draw Major Charged Intermediate Iarrow_forwardNH (aq)+CNO (aq) → CO(NH2)2(s) Experiment [NH4] (M) [CNO] (M) Initial rate (M/s) 1 0.014 0.02 0.002 23 0.028 0.02 0.008 0.014 0.01 0.001 Calculate the rate contant for this reaction using the data provided in the table.arrow_forward2CIO2 + 20H-1 CIO31 + CIO2 + H2O Experiment [CIO2], M [OH-1], M 1 0.0500 0.100 23 2 0.100 0.100 3 0.100 0.0500 Initial Rate, M/s 0.0575 0.230 0.115 ... Given this date, calculate the overall order of this reaction.arrow_forward
- 2 3 .(be)_[Ɔ+(be)_OI ← (b²)_IƆO+ (be)_I Experiment [1-] M 0.005 [OCI-] 0.005 Initial Rate M/min 0.000275 0.0025 0.005 0.000138 0.0025 0.0025 0.000069 4 0.0025 0.0025 0.000140 Calculate the rate constant of this reaction using the table data.arrow_forward1 2 3 4 I(aq) +OCl(aq) → IO¯¯(aq) + Cl¯(aq) Experiment [I-] M 0.005 [OCI-] 0.005 Initial Rate M/min 0.000275 0.0025 0.005 0.000138 0.0025 0.0025 Calculate the overall order of this reaction using the table data. 0.0025 0.000069 0.0025 0.000140arrow_forwardH2O2(aq) +3 I¯(aq) +2 H+(aq) → 13(aq) +2 H₂O(l)· ••• Experiment [H2 O2]o (M) [I]o (M) [H+]。 (M) Initial rate (M/s) 1 0.15 0.15 0.05 0.00012 234 0.15 0.3 0.05 0.00024 0.3 0.15 0.05 0.00024 0.15 0.15 0.1 0.00048 Calculate the overall order of this reaction using the table data.arrow_forward
- The U. S. Environmental Protection Agency (EPA) sets limits on healthful levels of air pollutants. The maximum level that the EPA considers safe for lead air pollution is 1.5 μg/m³ Part A If your lungs were filled with air containing this level of lead, how many lead atoms would be in your lungs? (Assume a total lung volume of 5.40 L.) ΜΕ ΑΣΦ = 2.35 1013 ? atoms ! Check your rounding. Your final answer should be rounded to 2 significant figures in the last step. No credit lost. Try again.arrow_forwardY= - 0.039 (14.01) + 0.7949arrow_forwardSuppose 1.76 g of magnesium acetate (Mg (CH3CO2)2) are dissolved in 140. mL of water. Find the composition of the resulting electrolyte solution. In particular, list the chemical symbols (including any charge) of each dissolved ion in the table below. List only one ion per row. mEq Then, calculate the concentration of each ion in dwrite the concentration in the second column of each row. Be sure you round your answers to the L correct number of significant digits. ion Add Row mEq L x 5arrow_forward
- A pdf file of your hand drawn, stepwise mechanisms for the reactions. For each reaction in the assignment, you must write each mechanism three times (there are 10 reactions, so 30 mechanisms). (A) do the work on a tablet and save as a pdf., it is expected to write each mechanism out and NOT copy and paste the mechanism after writing it just once. Everything should be drawn out stepwise and every bond that is formed and broken in the process of the reaction, and is expected to see all relevant lone pair electrons and curved arrows.arrow_forwardNonearrow_forwardNonearrow_forward
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