Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Chapter 12, Problem 99E
Interpretation Introduction
Interpretation:
The electron dot formula and the structural formula for
Concept introduction:
The Lewis structures are also known as electron dot structures. In the Lewis structure, electrons are denoted by dots. These dots represent the number of electrons present in the outer most shell of an element. The electron pairs shared by the atoms are termed as bonding electrons. Other electrons which do not participate in bond formation but complete the octet around each atom are termed as nonbonding electrons or lone pairs.
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AG/F-2° V
3. Before proceeding with this problem you may want to glance at p. 466 of your textbook
where various oxo-phosphorus derivatives and their oxidation states are summarized.
Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14:
-0.93
+0.38
-0.50
-0.51 -0.06
H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3
Acidic solution
Basic solution
-0.28
-0.50
3--1.12
-1.57
-2.05 -0.89
PO HPO H₂PO₂ →P → PH3
-1.73
a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the
formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both
processes; comment.
(3 points)
0.5
PH
P
0.0
-0.5
-1.0-
-1.5-
-2.0
H.PO,
-2.3+
-3 -2
-1
1
2
3
2
H,PO,
b) Frost diagram for phosphorus under acidic
conditions is shown. Identify possible
disproportionation and comproportionation processes;
write out chemical equations describing them. (2 points)
H,PO
4
S
Oxidation stale, N
4. For the following complexes, draw the structures and give a d-electron count of the
metal:
a) Tris(acetylacetonato)iron(III)
b) Hexabromoplatinate(2-)
c) Potassium diamminetetrabromocobaltate(III)
(6 points)
2. Calculate the overall formation constant for [Fe(CN)6]³, given that the overall formation
constant for [Fe(CN)6] 4 is ~1032, and that:
Fe3+ (aq) + e
= Fe²+ (aq)
E° = +0.77 V
[Fe(CN)6]³ (aq) + e¯ = [Fe(CN)6] (aq) E° = +0.36 V
(4 points)
Chapter 12 Solutions
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
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