Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Chapter 12, Problem 42E
Interpretation Introduction

(a)

Interpretation:

The electron dot formula and structural formula of PO43 are to be drawn.

Concept introduction:

An electron dot formula is a way of representing the molecular structure in which electrons are represented by a dot. Structural formula is a way in which atoms are linked together through a solid line. This solid line represents the covalent bond. An electron dot structure is known as Lewis structure. Electron dot structure indicates the valence electrons of an atom which are involved in bonding.

Expert Solution
Check Mark

Answer to Problem 42E

Electron dot structure and structural formula of PO43 are shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  1

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  2

Explanation of Solution

In molecule PO43 phosphorous is present as a central atom and oxygen is present as the surrounding atom of phosphorous. Phosphorous has 5 valence electrons and oxygen has 6 valence electrons. Negative charge present on the molecule indicates that three electrons are gained by the atom of the molecule. Total number of electron pairs is calculated by adding the valence electrons and the negative charge present on the molecule. So, number of electrons is (6+5+3) which is 14. Total electrons present in each bond pair is 2. Rest of the electrons are present as the lone pairs on oxygen atoms. An electron dot structure and structural formula of PO43 is shown below in Figure 1 and 2 respectively.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  3

Figure 1

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  4

Figure 2

Solid line, in Figure 2, between the phosphorous and oxygen atom is the covalent bond which is made up of two electrons. This bond is formed by sharing of electrons between the atoms present in that bond.

Conclusion

An electron dot structure and structural formula of PO43 are shown above in Figure 1 and Figure 2.

Interpretation Introduction

(b)

Interpretation:

The electron dot formula and structural formula of HPO42 are to be drawn.

Concept introduction:

An electron dot formula is a way of representing the molecular structure in which electrons are represented by a dot. Structural formula is a way in which atoms are linked together through a solid line. This solid line represents the covalent bond. An electron dot structure is known as Lewis structure. Electron dot structure indicates the valence electrons of an atom which are involved in bonding.

Expert Solution
Check Mark

Answer to Problem 42E

Electron dot structure and structural formula of HPO42 are shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  5

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  6

Explanation of Solution

In molecule HPO42, phosphorous is the central atom and surrounding atom of phosphorous is oxygen. Phosphorous has 5 valence electrons and oxygen has 6 valence electrons. Negative charge present on the molecule indicates that two electrons are gained by the molecule. Total number of electron pairs is calculated by adding the valence electrons and the negative charge present on the molecule. So, number of electrons is (6+6+6+6+5+1+2) which is 32. This shows that total electrons must be 32 or 16 pair of electrons. Total electrons present in each bond pair is 2. Rest of the electrons are present as the lone pair on phosphorous and oxygen atoms. An electron dot structure and structural formula of HPO42 is shown below in Figure 3 and 4 respectively.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  7

Figure 3

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  8

Figure 4

Each solid line, in Figure 4, between the phosphorous and oxygen atom is the covalent bond which is made up of two electrons. This bond is formed by sharing of electrons between the central atom phosphorous and the surrounding oxygen atoms.

Conclusion

An electron dot structure and structural formula of HPO42 are shown above in Figure 3 and Figure 4.

Interpretation Introduction

(c)

Interpretation:

The electron dot formula and structural formula of PO33 are to be drawn.

Concept introduction:

An electron dot formula is a way of representing the molecular structure in which electrons are represented by a dot. Structural formula is a way in which atoms are linked together through a solid line. This solid line represents the covalent bond. An electron dot structure is known as Lewis structure. Electron dot structure indicates the valence electrons of an atom which are involved in bonding.

Expert Solution
Check Mark

Answer to Problem 42E

Electron dot structure and structural formula of PO33 are shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  9

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  10

Explanation of Solution

In molecule PO33, phosphorous is the central atom and surrounding atom of phosphorous is oxygen. Phosphorous has 5 valence electrons and oxygen has 6 valence electrons. Negative charge present on the molecule indicates that three electrons are gained by the the molecule. Total number of electron pairs is calculated by adding the valence electrons and the negative charge present on the molecule. So, number of electrons is (6+6+6+5+3) which is 26. This shows that total electrons must be 26 or 13 pair of electrons. Total electrons present in each bond pair is 2. Rest of the electrons are present as the lone pair on phosphorous and oxygen atoms. An electron dot structure and structural formula of PO33 is shown below in Figure 5 and 6 respectively.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  11

Figure 5

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  12

Figure 6

Each solid line, in Figure 6, between the phosphorous and oxygen atom is the covalent bond which is made up of two electrons. This bond is formed by sharing of electrons between the central atom and the surrounding atom.

Conclusion

An electron dot structure and structural formula of PO33 are shown above in Figure 5 and Figure 6.

Interpretation Introduction

(d)

Interpretation:

The electron dot formula and structural formula of HPO32 are to be drawn.

Concept introduction:

An electron dot formula is a way of representing the molecular structure in which electrons are represented by a dot. Structural formula is a way in which atoms are linked together through a solid line. This solid line represents the covalent bond. An electron dot structure is known as Lewis structure. Electron dot structure indicates the valence electrons of an atom which are involved in bonding.

Expert Solution
Check Mark

Answer to Problem 42E

Electron dot structure and structural formula of HPO32 are shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  13

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  14

Explanation of Solution

In molecule HPO32, phosphorous is the central atom and surrounding atom of phosphorous is oxygen. Phosphorous has 5 valence electrons and oxygen has 6 valence electrons. Negative charge present on the molecule indicates that two electrons are gained by the molecule. Total number of electron pairs is calculated by adding the valence electrons and the negative charge present on the molecule. So, number of electrons is (6+6+6+5+2+1) which is 28. This shows that total electrons must be 28 or 14 pair of electrons. Total electrons present in each bond pair is 2. Rest of the electrons are present as the lone pair on phosphorous and oxygen atoms. An electron dot structure and structural formula of HPO32 is shown below in Figure 7 and 8 respectively.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  15

Figure 7

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 42E , additional homework tip  16

Figure 8

Each solid line, in Figure 8, between the phosphorous and oxygen atom is the covalent bond which is made up of two electrons. This bond is formed by sharing of electrons between the central atom and the surrounding atom.

Conclusion

An electron dot structure and structural formula of HPO32 are shown above in Figure 7 and Figure 8.

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Chapter 12 Solutions

Introductory Chemistry: Concepts and Critical Thinking (8th Edition)

Ch. 12 - Prob. 11CECh. 12 - Prob. 12CECh. 12 - Prob. 1KTCh. 12 - Prob. 2KTCh. 12 - Prob. 3KTCh. 12 - Prob. 4KTCh. 12 - Prob. 5KTCh. 12 - Prob. 6KTCh. 12 - Prob. 7KTCh. 12 - Prob. 8KTCh. 12 - Prob. 9KTCh. 12 - Prob. 10KTCh. 12 - Prob. 11KTCh. 12 - Prob. 12KTCh. 12 - Prob. 13KTCh. 12 - Prob. 14KTCh. 12 - Prob. 15KTCh. 12 - Prob. 16KTCh. 12 - Prob. 17KTCh. 12 - Prob. 18KTCh. 12 - Prob. 19KTCh. 12 - Prob. 20KTCh. 12 - Prob. 21KTCh. 12 - Prob. 22KTCh. 12 - Prob. 23KTCh. 12 - Prob. 24KTCh. 12 - Prob. 25KTCh. 12 - Prob. 26KTCh. 12 - Prob. 27KTCh. 12 - Prob. 28KTCh. 12 - Prob. 29KTCh. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Prob. 11ECh. 12 - Prob. 12ECh. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Prob. 15ECh. 12 - Prob. 16ECh. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - Prob. 22ECh. 12 - Prob. 23ECh. 12 - Prob. 24ECh. 12 - Prob. 25ECh. 12 - Prob. 26ECh. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Prob. 29ECh. 12 - Prob. 30ECh. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Prob. 33ECh. 12 - Prob. 34ECh. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - Prob. 37ECh. 12 - Prob. 38ECh. 12 - Prob. 39ECh. 12 - Prob. 40ECh. 12 - Prob. 41ECh. 12 - Prob. 42ECh. 12 - Prob. 43ECh. 12 - Prob. 44ECh. 12 - Prob. 45ECh. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Prob. 49ECh. 12 - Prob. 50ECh. 12 - Prob. 51ECh. 12 - Prob. 52ECh. 12 - Prob. 53ECh. 12 - Prob. 54ECh. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - Prob. 58ECh. 12 - Prob. 59ECh. 12 - Prob. 60ECh. 12 - Prob. 61ECh. 12 - Prob. 62ECh. 12 - Prob. 63ECh. 12 - Prob. 64ECh. 12 - Prob. 65ECh. 12 - Prob. 66ECh. 12 - Prob. 67ECh. 12 - Prob. 68ECh. 12 - Prob. 69ECh. 12 - Prob. 70ECh. 12 - Prob. 71ECh. 12 - Prob. 72ECh. 12 - Prob. 73ECh. 12 - Prob. 74ECh. 12 - Prob. 75ECh. 12 - Prob. 76ECh. 12 - Prob. 77ECh. 12 - Prob. 78ECh. 12 - Prob. 79ECh. 12 - Prob. 80ECh. 12 - Prob. 81ECh. 12 - Prob. 82ECh. 12 - Prob. 83ECh. 12 - Prob. 84ECh. 12 - Prob. 85ECh. 12 - Prob. 86ECh. 12 - Prob. 87ECh. 12 - Prob. 88ECh. 12 - Prob. 89ECh. 12 - Prob. 90ECh. 12 - Prob. 91ECh. 12 - Prob. 92ECh. 12 - Prob. 93ECh. 12 - Prob. 94ECh. 12 - Prob. 95ECh. 12 - Prob. 96ECh. 12 - Prob. 97ECh. 12 - Prob. 98ECh. 12 - Prob. 99ECh. 12 - Prob. 100ECh. 12 - Prob. 1STCh. 12 - Prob. 2STCh. 12 - Prob. 3STCh. 12 - Prob. 4STCh. 12 - Prob. 5STCh. 12 - Prob. 6STCh. 12 - Prob. 7STCh. 12 - Prob. 8STCh. 12 - Prob. 9STCh. 12 - Prob. 10STCh. 12 - Prob. 11STCh. 12 - Prob. 12STCh. 12 - Prob. 13STCh. 12 - Prob. 14STCh. 12 - Prob. 15STCh. 12 - Prob. 16STCh. 12 - Prob. 17STCh. 12 - Prob. 18ST
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