Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
Question
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Chapter 12, Problem 40E
Interpretation Introduction

(a)

Interpretation:

The electron dot formula and structural formula of BrO is to be drawn.

Concept introduction:

An electron dot formula is a way of representing the molecular structure in which electrons are represented by a dot. Structural formula is a way in which atoms are linked together through a solid line. This solid line represents the covalent bond. An electron dot structure is known as Lewis structure. Electron dot structure indicates the valence electrons of an atom which are involved in bonding.

Expert Solution
Check Mark

Answer to Problem 40E

Electron dot structure of BrO is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  1

The structural formula of BrO is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  2

Explanation of Solution

In molecule BrO bromine and oxygen are present as the bonding atoms. Bromine has 7 valence electrons and oxygen has 6 valence electrons. Negative charge is present on the molecule indicates that one electron is gained by the any atom of the molecule. Total number of electron pairs is calculated by adding the valence electrons and the negative charge present on the molecule. So, number of electrons is (6+7+1) which is 14. This shows that total electrons must be 14. Total electrons present in bond pair is 2. Rest of the electrons are present as the lone pairs on bromine and oxygen atom. An electron dot structure and structural formula of BrO is shown below in Figure 1 and 2 respectively.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  3

Figure 1

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  4

Figure 2

Solid line, in Figure 2, between the bromine and oxygen atom is the covalent bond which is made up of two electrons. This bond is formed by sharing of electrons between the atoms present in that bond.

Conclusion

An electron dot structure and structural formula of BrO is shown above in Figure 1 and Figure 2.

Interpretation Introduction

(b)

Interpretation:

The electron dot formula and structural formula of BrO2 is to be drawn.

Concept introduction:

An electron dot formula is a way of representing the molecular structure in which electrons are represented by a dot. Structural formula is a way in which atoms are linked together through a solid line. This solid line represents the covalent bond. An electron dot structure is known as Lewis structure. Electron dot structure indicates the valence electrons of an atom which are involved in bonding.

Expert Solution
Check Mark

Answer to Problem 40E

Electron dot structure of BrO2 is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  5

The structural formula of BrO2 is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  6

Explanation of Solution

In molecule BrO2, bromine is the central atom and and oxygen is present as the surrounding atoms. Bromine has 7 valence electrons and oxygen has 6 valence electrons. Negative charge is present on the molecule indicates that one electron is gained by the atom of the molecule. Total number of electron pairs is calculated by adding the valence electrons and the negative charge present on the molecule. So, number of electrons is (6+6+7+1) which is 20. This shows that total electrons must be 20 or 10 pair of electrons. Total electrons present in each bond pair is 2. Rest of the electrons are present as the lone pair on bromine and oxygen atoms. An electron dot structure and structural formula of BrO2 is shown below in Figure 3 and 4 respectively.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  7

Figure 3

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  8

Figure 4

Each solid line, in Figure 4, between the bromine and oxygen atom is the covalent bond which is made up of two electrons. This bond is formed by sharing of electrons between the central atom bromine and the surrounding oxygen atom.

Conclusion

An electron dot structure and structural formula of BrO2 is shown above in Figure 3 and Figure 4.

Interpretation Introduction

(c)

Interpretation:

The electron dot formula and structural formula of BrO3 is to be drawn.

Concept introduction:

An electron dot formula is a way of representing the molecular structure in which electrons are represented by a dot. Structural formula is a way in which atoms are linked together through a solid line. This solid line represents the covalent bond. An electron dot structure is known as Lewis structure. Electron dot structure indicates the valence electrons of an atom which are involved in bonding.

Expert Solution
Check Mark

Answer to Problem 40E

Electron dot structure of BrO3 is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  9

The structural formula of BrO3 is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  10

Explanation of Solution

In molecule BrO3, bromine is the central atom and and oxygen is present as the surrounding atoms. Bromine has 7 valence electrons and oxygen has 6 valence electrons. Negative charge is present on the molecule indicates that one electron is gained by the atom of the molecule. Total number of electron pairs is calculated by adding the valence electrons and the negative charge present on the molecule. So, number of electrons is (6+6+6+7+1) which is 26. This shows that total electrons must be 26 or 13 pair of electrons. Total electrons present in each bond pair is 2. Rest of the electrons are present as the lone pair on bromine and oxygen atoms. An electron dot structure and structural formula of BrO3 is shown below in Figure 5 and 6 respectively.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  11

Figure 5

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  12

Figure 6

Each solid line, in Figure 6, between the bromine and oxygen atom is the covalent bond which is made up of two electrons. This bond is formed by sharing of electrons between the central atom bromine and the surrounding oxygen atom.

Conclusion

An electron dot structure and structural formula of BrO3 is shown above in Figure 5 and Figure 6.

Interpretation Introduction

(d)

Interpretation:

The electron dot formula and structural formula of BrO4 is to be drawn.

Concept introduction:

An electron dot formula is a way of representing the molecular structure in which electrons are represented by a dot. Structural formula is a way in which atoms are linked together through a solid line. This solid line represents the covalent bond. An electron dot structure is known as Lewis structure. Electron dot structure indicates the valence electrons of an atom which are involved in bonding.

Expert Solution
Check Mark

Answer to Problem 40E

Electron dot structure of BrO4 is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  13

The structural formula of BrO4 is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  14

Explanation of Solution

In molecule BrO4, bromine is the central atom and and oxygen is present as the surrounding atoms. Bromine has 7 valence electrons and oxygen has 6 valence electrons. Negative charge is present on the molecule indicates that one electron is gained by the atom of the molecule. Total number of electron pairs is calculated by adding the valence electrons and the negative charge present on the molecule. So, number of electrons is (6+6+6+6+7+1) which is 32. This shows that total electrons must be 32 or 16 pair of electrons. Total electrons present in each bond pair is 2. Rest of the electrons are present as the lone pair on bromine and oxygen atoms. An electron dot structure and structural formula of BrO4 is shown below in Figure 7 and 8 respectively.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  15

Figure 7

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 12, Problem 40E , additional homework tip  16

Figure 8

Each solid line in Figure 8, between the bromine and oxygen atom is the covalent bond which is made up of two electrons. This bond is formed by sharing of electrons between the central atom bromine and the surrounding oxygen atoms.

Conclusion

An electron dot structure and structural formula of BrO4 is shown above in Figure 7 and Figure 8.

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Chapter 12 Solutions

Introductory Chemistry: Concepts and Critical Thinking (8th Edition)

Ch. 12 - Prob. 11CECh. 12 - Prob. 12CECh. 12 - Prob. 1KTCh. 12 - Prob. 2KTCh. 12 - Prob. 3KTCh. 12 - Prob. 4KTCh. 12 - Prob. 5KTCh. 12 - Prob. 6KTCh. 12 - Prob. 7KTCh. 12 - Prob. 8KTCh. 12 - Prob. 9KTCh. 12 - Prob. 10KTCh. 12 - Prob. 11KTCh. 12 - Prob. 12KTCh. 12 - Prob. 13KTCh. 12 - Prob. 14KTCh. 12 - Prob. 15KTCh. 12 - Prob. 16KTCh. 12 - Prob. 17KTCh. 12 - Prob. 18KTCh. 12 - Prob. 19KTCh. 12 - Prob. 20KTCh. 12 - Prob. 21KTCh. 12 - Prob. 22KTCh. 12 - Prob. 23KTCh. 12 - Prob. 24KTCh. 12 - Prob. 25KTCh. 12 - Prob. 26KTCh. 12 - Prob. 27KTCh. 12 - Prob. 28KTCh. 12 - Prob. 29KTCh. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Prob. 11ECh. 12 - Prob. 12ECh. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Prob. 15ECh. 12 - Prob. 16ECh. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - Prob. 22ECh. 12 - Prob. 23ECh. 12 - Prob. 24ECh. 12 - Prob. 25ECh. 12 - Prob. 26ECh. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Prob. 29ECh. 12 - Prob. 30ECh. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Prob. 33ECh. 12 - Prob. 34ECh. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - Prob. 37ECh. 12 - Prob. 38ECh. 12 - Prob. 39ECh. 12 - Prob. 40ECh. 12 - Prob. 41ECh. 12 - Prob. 42ECh. 12 - Prob. 43ECh. 12 - Prob. 44ECh. 12 - Prob. 45ECh. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Prob. 49ECh. 12 - Prob. 50ECh. 12 - Prob. 51ECh. 12 - Prob. 52ECh. 12 - Prob. 53ECh. 12 - Prob. 54ECh. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - Prob. 58ECh. 12 - Prob. 59ECh. 12 - Prob. 60ECh. 12 - Prob. 61ECh. 12 - Prob. 62ECh. 12 - Prob. 63ECh. 12 - Prob. 64ECh. 12 - Prob. 65ECh. 12 - Prob. 66ECh. 12 - Prob. 67ECh. 12 - Prob. 68ECh. 12 - Prob. 69ECh. 12 - Prob. 70ECh. 12 - Prob. 71ECh. 12 - Prob. 72ECh. 12 - Prob. 73ECh. 12 - Prob. 74ECh. 12 - Prob. 75ECh. 12 - Prob. 76ECh. 12 - Prob. 77ECh. 12 - Prob. 78ECh. 12 - Prob. 79ECh. 12 - Prob. 80ECh. 12 - Prob. 81ECh. 12 - Prob. 82ECh. 12 - Prob. 83ECh. 12 - Prob. 84ECh. 12 - Prob. 85ECh. 12 - Prob. 86ECh. 12 - Prob. 87ECh. 12 - Prob. 88ECh. 12 - Prob. 89ECh. 12 - Prob. 90ECh. 12 - Prob. 91ECh. 12 - Prob. 92ECh. 12 - Prob. 93ECh. 12 - Prob. 94ECh. 12 - Prob. 95ECh. 12 - Prob. 96ECh. 12 - Prob. 97ECh. 12 - Prob. 98ECh. 12 - Prob. 99ECh. 12 - Prob. 100ECh. 12 - Prob. 1STCh. 12 - Prob. 2STCh. 12 - Prob. 3STCh. 12 - Prob. 4STCh. 12 - Prob. 5STCh. 12 - Prob. 6STCh. 12 - Prob. 7STCh. 12 - Prob. 8STCh. 12 - Prob. 9STCh. 12 - Prob. 10STCh. 12 - Prob. 11STCh. 12 - Prob. 12STCh. 12 - Prob. 13STCh. 12 - Prob. 14STCh. 12 - Prob. 15STCh. 12 - Prob. 16STCh. 12 - Prob. 17STCh. 12 - Prob. 18ST
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