Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Chapter 12, Problem 47E
Interpretation Introduction
Interpretation:
Whether the metals or non-metals are more electronegative is to be stated.
Concept introduction:
Electronegativity is a term which describes the tendency of any species to pull the shared pair of electrons towards itself. More is the electronegativity of an element; more is the attraction of electron pairs towards itself. In a given
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AG/F-2° V
3. Before proceeding with this problem you may want to glance at p. 466 of your textbook
where various oxo-phosphorus derivatives and their oxidation states are summarized.
Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14:
-0.93
+0.38
-0.50
-0.51 -0.06
H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3
Acidic solution
Basic solution
-0.28
-0.50
3--1.12
-1.57
-2.05 -0.89
PO HPO H₂PO₂ →P → PH3
-1.73
a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the
formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both
processes; comment.
(3 points)
0.5
PH
P
0.0
-0.5
-1.0-
-1.5-
-2.0
H.PO,
-2.3+
-3 -2
-1
1
2
3
2
H,PO,
b) Frost diagram for phosphorus under acidic
conditions is shown. Identify possible
disproportionation and comproportionation processes;
write out chemical equations describing them. (2 points)
H,PO
4
S
Oxidation stale, N
4. For the following complexes, draw the structures and give a d-electron count of the
metal:
a) Tris(acetylacetonato)iron(III)
b) Hexabromoplatinate(2-)
c) Potassium diamminetetrabromocobaltate(III)
(6 points)
2. Calculate the overall formation constant for [Fe(CN)6]³, given that the overall formation
constant for [Fe(CN)6] 4 is ~1032, and that:
Fe3+ (aq) + e
= Fe²+ (aq)
E° = +0.77 V
[Fe(CN)6]³ (aq) + e¯ = [Fe(CN)6] (aq) E° = +0.36 V
(4 points)
Chapter 12 Solutions
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
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- What is the missing reactant R in this organic reaction? N N H3O+ +R + • Draw the structure of R in the drawing area below. • Be sure to use wedge and dash bonds if it's necessary to draw one particular enantiomer. Click and drag to start drawing a structure. fmarrow_forwardThe product on the right-hand side of this reaction can be prepared from two organic reactants, under the conditions shown above and below the arrow. Draw 1 and 2 below, in any arrangement you like. 1+2 NaBH3CN H+ N Click and drag to start drawing a structure. 5arrow_forwardAssign this HSQC Spectrum ( please editing clearly on the image)arrow_forward
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- elow are experimentally determined van Deemter plots of column efficiency, H, vs. flow rate. H is a quantitative measurement of band broadening. The left plot is for a liquid chromatography application and the night is for gas chromatography. Compare and contrast these two plots in terms of the three band broadening mechanisms presented in this activity. How are they similar? How do they differ? Justify your answers.? 0.4 H (mm) 0.2 0.1- 0.3- 0 0.5 H (mm) 8.0 7.0 6.0 5.0 4.0- 3.0 T +++ 1.0 1.5 0 2.0 4.0 Flow Rate, u (cm/s) 6.0 8.0 Flow Rate, u (cm/s)arrow_forwardPredict the products of this organic reaction: + H ZH NaBH3CN H+ n. ? Click and drag to start drawing a structure. Xarrow_forwardWhat is the missing reactant R in this organic reaction? + R H3O+ + • Draw the structure of R in the drawing area below. • Be sure to use wedge and dash bonds if it's necessary to draw one particular enantiomer. Click and drag to start drawing a structure.arrow_forward
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