Concept explainers
(a)
Interpretation:
To name and draw structural formula for
Concept Introduction:
Isomers are the compounds that have same molecular formula but different structural formula.
Cis-trans isomerism arises in the compounds when there is a difference in the orientation of the two same groups.
When two same groups are along the same side of the C-C bond it is called as cis isomer, but when the same groups lie opposite to each other along the C-C bond. It is said to be trans isomer.
Example- Cis-1,2-dibromo ethane and trans-1,2, dibromo ethane are cis-trans isomers.

Answer to Problem 6P
The alkenes with the molecular formula
Explanation of Solution
The longest chain for the given skeleton has 5 carbons therefore the root name prop- is used here. The alkenes with the molecular formula
In this isomer, it contains 6 carbons and 12 hydrogen atoms, thus the molecular formula is
In this isomer, it contains 6 carbons and 12 hydrogen atoms, thus the molecular formula is
In this isomer, it contains 6 carbons and 12 hydrogen atoms, thus the molecular formula is
In this isomer, it contains 6 carbons and 12 hydrogen atoms, thus the molecular formula is
(b)
Interpretation:
To name and draw structural formula for alkenes with the molecular formula
Concept Introduction:
Isomers are the compounds that have same molecular formula but different structural formula.
Cis-trans isomerism arises in the compounds when there is a difference in the orientation of the two same groups.
When two same groups are along the same side of the C-C bond it is called as cis isomer, but when the same groups lie opposite to each other along the C-C bond. It is said to be trans isomer.
Example- Cis-1,2-dibromo ethane and trans-1,2, dibromo ethane are cis-trans isomers.

Answer to Problem 6P
The alkenes with the molecular formula
Explanation of Solution
The longest chain for the given skeleton has 4 carbons therefore the root name but- is used here. The alkenes with the molecular formula
In this isomer, it contains 6 carbons and 12 hydrogen atoms, thus the molecular formula is
In this isomer, it contains 6 carbons and 12 hydrogen atoms, thus the molecular formula is
(c)
Interpretation:
To name and draw structural formula for alkenes with the molecular formula
Concept Introduction:
Isomers are the compounds that have same molecular formula but different structural formula.
Cis-trans isomerism arises in the compounds when there is a difference in the orientation of the two same groups.
When two same groups are along the same side of the C-C bond it is called as cis isomer, but when the same groups lie opposite to each other along the C-C bond. It is said to be trans isomer.
Example- Cis-1,2-dibromo ethane and trans-1,2, dibromo ethane are cis-trans isomers.

Answer to Problem 6P
The alkene with the molecular formula
Explanation of Solution
The longest chain for the given skeleton has 4 carbons therefore the root name but- is used here. The alkene with the molecular formula
In this isomer, it contains 6 carbons and 12 hydrogen atoms, thus the molecular formula is
(c)
Interpretation:
To name and draw structural formula for alkenes with the molecular formula
Concept Introduction:
Isomers are the compounds that have same molecular formula but different structural formula.
Cis-trans isomerism arises in the compounds when there is a difference in the orientation of the two same groups.
When two same groups are along the same side of the C-C bond it is called as cis isomer, but when the same groups lie opposite to each other along the C-C bond. It is said to be trans isomer.
Example- Cis-1,2-dibromo ethane and trans-1,2, dibromo ethane are cis-trans isomers.

Answer to Problem 6P
The alkene with the molecular formula
Explanation of Solution
The longest chain for the given skeleton has 4 carbons therefore the root name but- is used here. The alkene with the molecular formula
In this isomer, it contains 6 carbons and 12 hydrogen atoms, thus the molecular formula is
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Chapter 12 Solutions
INTRO.TO GENERAL,ORGAN...-OWLV2 ACCESS
- Draw the major product of this reaction. Ignore inorganic byproducts. ○ O 1. H₂O, pyridine 2. neutralizing work-up a N W X 人 Parrow_forward✓ Check the box under each molecule that has a total of five ẞ hydrogens. If none of the molecules fit this description, check the box underneath the table. tab OH CI 0 Br xx Br None of these molecules have a total of five ẞ hydrogens. esc Explanation Check caps lock shift 1 fn control 02 F2 W Q A N #3 S 80 F3 E $ t 01 205 % 5 F5 & 7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility FT * 8 R T Y U כ F6 9 FIG F11 F D G H J K L C X V B < N M H option command P H + F12 commandarrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts and the carboxylic acid side product. O 1. CHзMgBr (excess) 2. H₂O ✓ W X 人arrow_forward
- If cyclopentyl acetaldehyde reacts with NaOH, state the product (formula).arrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. N S S HgCl2, H2SO4 く 8 W X Parrow_forwardtab esc く Drawing the After running various experiments, you determine that the mechanism for the following reaction occurs in a step-wise fashion. Br + OH + Using this information, draw the correct mechanism in the space below. 1 Explanation Check F2 F1 @2 Q W A os lock control option T S # 3 80 F3 Br $ 4 0105 % OH2 + Br Add/Remove step X C F5 F6 6 R E T Y 29 & 7 F D G H Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce A F7 DII F8 C Ո 8 * 9 4 F10 F C J K L C V Z X B N M H command P ge Coarrow_forward
- Indicate compound A that must react with ethylbenzene to obtain 4-ethylbenzene-1-sulfonic acid. 3-bromo-4-ethylbenzene-1-sulfonic acid.arrow_forwardPart 1 of 2 Draw the structure of A, the minor E1 product of the reaction. esc I Skip Part Check H₂O, D 2 A + Click and drag to start drawing a structure. -0- F1 F2 1 2 # 3 Q A 80 F3 W E S D F4 $ 4 % 5 F5 ㅇ F6 R T Y F G X 5 & 7 + Save 2025 McGraw Hill LLC. All Rights Reserved. DII F7 F8 H * C 80 J Z X C V B N 4 F9 6arrow_forwardFile Preview The following is a total synthesis of the pheromone of the western pine beetle. Such syntheses are interesting both because of the organic chemistry, and because of the possibility of using species specific insecticides, rather than broad band insecticides. Provide the reagents for each step. There is some chemistry from our most recent chapter in this synthesis, but other steps are review from earlier chapters. (8 points) COOEt COOEt A C COOEt COOEt COOH B OH OTS CN D E See the last homework set F for assistance on this one. H+, H₂O G OH OH The last step is just nucleophilic addition reactions, taking the ketone to an acetal, intramolecularly. But it is hard to visualize the three dimensional shape as it occurs. Frontalin, pheromone of the western pine beetlearrow_forward
- For the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. C Major Product: Check + ◎ + X ง © Cl I F2 80 F3 I σ F4 I F5 NaOH Click and drawing F6 A 2025 McGraw Hill LLC. All Rights E F7 F8 $ # % & 2 3 4 5 6 7 8 Q W E R T Y U A S D F G H Jarrow_forwardCan I please get help with this graph. If you can show exactly where it needs to pass through.arrow_forwardN Draw the major product of this reaction. Ignore inorganic byproducts. D 1. H₂O, pyridine 2. neutralizing work-up V P W X DE CO e C Larrow_forward
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