Explanation 1) Concept: The force of one sphere on the other is directed along center - centerline. As seen from the figure, the force from the sphere would be along 45 ° and forces from the wall on the balls would be perpendicular. Therefore, we can resolve the forces and write the equations for vertical and horizontal directions of the forces. Solving this, we would get the forces in terms of weight. 2) Equation: F = F s i n θ + F c o s θ 3) Given: The mass of spheres and angle of force between them. Hint: The force of one sphere on the other is directed along the center–center line. 4) Calculations: First, we have to resolve all the forces along the X and Y-axis. Then we get the forces on the upper sphere. As shown in the figure: F w a l l = F c o s 45 a n d F s i n 45 = m g As well as forces on the bottom sphere. F f l o o r ' = F s i n 45 + m g a n d F w a l l ' = F c o s 45 a) By solving above equations we get F f l o o r ' = F s i n

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ISBN: 9781118230725

Author: David Halliday, Robert Resnick, Jearl Walker

Publisher: Wiley, John & Sons, Incorporated

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Chapter 12, Problem 64P

To determine

To find:

the magnitude of forces on the sphere

a) from the bottom of container

b) from the left side of container

c) from the right side of container

d) on each other

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Chapter 12, Problem 63P

Chapter 12, Problem 65P

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the magnitude of forces on the sphere a) from the bottom of container b) from the left side of container c) from the right side of container d) on each other

Solution Summary: The author explains that the force of one sphere on the other is directed along the center - centerline.

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To find: the magnitude of forces on the sphere a) from the bottom of container b) from the left side of container c) from the right side of container d) on each other

Want to see the full answer?

Chapter 12 Solutions

To find:

the magnitude of forces on the sphere

a) from the bottom of container

b) from the left side of container

c) from the right side of container

d) on each other