Chapter 12, Problem 47A

To determine

Specific heat of metal.

Answer to Problem 47A

  $C=1003.2\text{J/kg}\cdot \text{K}$

Explanation of Solution

Given:

Mass of metal block, $m=5\times {10}^2\text{g}=0.5\text{kg}$

Change in temperature, $\Delta T=30°\text{C}-20°\text{C}=10°\text{C}$

Heat absorbed by metal is , $Q=5016\text{J}$

Formula Used:

Specific heat formula,

  $Q=mC\Delta T$

Here, $Q$ is heat energy, $m$ is mass, $C$ is specific heat, and $\Delta T$ is change in temperature.

Calculation:

To find the specific heat of metal, substitute the given values in the above formula.

  $\begin{array}{c}C=\frac{Q}{m\Delta T}\\ =\frac{5016}{0.5\times \left(30°-20°\right)}\\ =1003.2\text{J/kg}\cdot \text{K}\end{array}$

Conclusion:

Therefore, specific heat of metal is $C=1003.2\text{J/kg}\cdot \text{K}$