Concept explainers
Work done by weight lifter.
Answer to Problem 86A
Explanation of Solution
Given:
Mass of barbell,
Height,
Formula used:
Here, U is potential energy, m is mass, g is acceleration due to gravity and h is height.
Calculation:
Work done in lifting the barbell will be equal to potential energy gained by the barbell.
Acceleration due to gravity on earth,
Now, putting the value of m, g and h.
Conclusion:
Therefore, work done in lifting the barbell is
Chapter 12 Solutions
Glencoe Physics: Principles and Problems, Student Edition
Additional Science Textbook Solutions
Chemistry: Structure and Properties (2nd Edition)
Organic Chemistry (8th Edition)
Chemistry: The Central Science (14th Edition)
Applications and Investigations in Earth Science (9th Edition)
Campbell Biology (11th Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
- No chatgpt plsarrow_forwardWhat is the current, in amps, across a conductor that has a resistance of10 Ω and a voltage of 20 V? 2. A conductor draws a current of 100 A and a resistance of 5 Ω. What is thevoltageacross the conductor? 3. What is the resistance, in ohm’s, of a conductor that has a voltage of 80 kVand acurrent of 200 mA? 4. An x-ray imaging system that draws a current of 90 A is supplied with 220V. What is the power consumed? 5. An x-ray is produced using 800 mA and 100 kV. What is the powerconsumed in kilowatts?arrow_forwardՍՈՈՒ XVirginia Western Community Coll x P Course Home X + astering.pearson.com/?courseld=13289599#/ Figure y (mm) x=0x = 0.0900 m All ✓ Correct For either the time for one full cycle is 0.040 s; this is the period. Part C - ON You are told that the two points x = 0 and x = 0.0900 m are within one wavelength of each other. If the wave is moving in the +x-direction, determine the wavelength. Express your answer to two significant figures and include the appropriate units. 0 t(s) λ = Value m 0.01 0.03 0.05 0.07 Copyright © 2025 Pearson Education Inc. All rights reserved. 日 F3 F4 F5 1775 % F6 F7 B F8 Submit Previous Answers Request Answer ? × Incorrect; Try Again; 3 attempts remaining | Terms of Use | Privacy Policy | Permissions | Contact Us | Cookie Settings 28°F Clear 4 9:23 PM 1/20/2025 F9 prt sc F10 home F11 end F12 insert delete 6 7 29 & * ( 8 9 0 t = back Οarrow_forward
- Part C Find the height yi from which the rock was launched. Express your answer in meters to three significant figures. Learning Goal: To practice Problem-Solving Strategy 4.1 for projectile motion problems. A rock thrown with speed 12.0 m/s and launch angle 30.0 ∘ (above the horizontal) travels a horizontal distance of d = 19.0 m before hitting the ground. From what height was the rock thrown? Use the value g = 9.800 m/s2 for the free-fall acceleration. PROBLEM-SOLVING STRATEGY 4.1 Projectile motion problems MODEL: Is it reasonable to ignore air resistance? If so, use the projectile motion model. VISUALIZE: Establish a coordinate system with the x-axis horizontal and the y-axis vertical. Define symbols and identify what the problem is trying to find. For a launch at angle θ, the initial velocity components are vix=v0cosθ and viy=v0sinθ. SOLVE: The acceleration is known: ax=0 and ay=−g. Thus, the problem becomes one of…arrow_forwardPhys 25arrow_forwardPhys 22arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON