Chapter 12, Problem 79A

To determine

To Write:A physics problem for which the given equation would be part of the solution.

Explanation of Solution

Introduction:

The given equation is:

  $75\text{J/K=}\frac{m\left(4180\text{J/kg}\cdot \text{K}\right)\left(260\text{K}-250\text{K}\right)}{250\text{K}}$

Change in entropy can be obtained by:

  $\Delta S=\frac{Q}{T}$

Where, Q is the thermal energy and T is the temperature.

Thermal energy can be obtained by:

  $Q=mc\Delta T$

Where, m is the mass, c is the specific heat and $\Delta T$ is the difference in temperature.

The specific heat of water is $4180\text{J/kg}\cdot \text{K}$ .

A physics problem for which the given equation would be part of the solution is:

Calculate the mass of water which is heated from 250 K to 260 K and has a change in entropy of $75\text{J/K}$ .