Chapter 12, Problem 57A

To determine

the amount of thermal energy that ice is going to absorb when it is melted.

Answer to Problem 57A

The heat absorbed by the ice as it melts is $\boxed{Q=67\times {10}^5\text{J}}$.

Explanation of Solution

Given:

Mass of the ice block is $m=20.0\text{kg}$ .

Initial temperature of the ice is $0.0°\text{C}$ .

Formula used:

The expression for heat or energy for an ice block can be expressed as

  $Q=m{H}_f$  ......( (1)

Here, $Q$ is the required heat, $m$ is the mass of the solid / ice, and $H_f$ is the heat of fusion of the solid/ice.

Calculation:

Heat of fusion of ice is $H_f=3.34\times {10}^5\text{J/kg}$ .

Substitute the values of $H_f$ , and $m$ in equation (1)

  $\begin{array}{l}Q=\left(20.0\text{kg}\right)\left(3.34\times {10}^5\text{J/kg}\right)\\ \boxed{Q=67\times {10}^5\text{J}}\end{array}$

Conclusion:

Hence, the heat absorbed by the ice as it melts is $\boxed{Q=67\times {10}^5\text{J}}$.