Chapter 12.1, Problem 1PP

To determine

To Calculate: The amount of thermal energy absorbed by a copper water pipe.

Answer to Problem 1PP

  $53\text{kJ}$

Explanation of Solution

Given:

Mass of copper water pipe, $m=2.3\text{kg}$

Change in temperature,

  $\begin{array}{c}\Delta T=T_2-T_1\\ =80°\text{C}-20°\text{C}\\ =60°\text{C}\end{array}$

Formula Used:

  $Q=mc\Delta T$

Where, m is the mass, c is the specific heat capacity and $\Delta T$ is the difference in temperature.

Calculations:

Specific heat capacity of Copperis $c=385\text{J/kg}\cdot \text{°C}$

Substitute the values and solve:

  $\begin{array}{c}Q=mc\Delta T\\ =\left(2.3\text{kg}\right)\left(385\text{J/kg}\cdot \text{°C}\right)\left(60°\text{C}\right)\\ =53130\text{J}\\ \approx 53\text{kJ}\end{array}$

Conclusion:

Thus, the amount of thermal energy absorbed by a copper water pipe is $53\text{kJ}$ .