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12-23 Draw a structural formula for each compound.
- 3-Chloropropene
- 3-Methylcyclohexene
- 1,2-Dimethylcyclohexene
- /runs-3,4-Dimethyl-3-heptene
- Cydopropene
- 3-Hexyne
(a)
Interpretation:
To draw the structural formula for the compound.
Concept Introduction:
Structural formula is the spatial arrangement of atoms of a molecule in space.
In the condensed formula is a line-angle formula, the symbol for carbon and hydrogen atoms are not shown. Only carbon-carbon bonds are shown using lines. Single bonds are shown as 
double bond as 
and triple bond as 
. The carbon atoms are represented as vertices and end of lines.
Answer to Problem 12.23P
Explanation of Solution
3-Chloropropene.
Carbon atoms in the longest chain are 3.
-ene means a double bond is present at Carbon 1.
Chlorine at Carbon 3.
Structure.
(b)
Interpretation:
To draw the structural formula for the compound.
Concept Introduction:
Structural formula is the spatial arrangement of atoms of a molecule in space. In the condensed formula is a line-angle formula, the symbol for carbon and hydrogen atoms are not shown. Only carbon-carbon bonds are shown using lines. Single bonds are shown as 
double bond as 
and triple bond as 
. The carbon atoms are represented as vertices and end of lines.
Answer to Problem 12.23P
Explanation of Solution
3-Methylcyclohexene.
Carbons in longest chain=6.
Cyclo means a cyclic hydrocarbon.
-ene means a double bond is present at Carbon 1.
Methyl at Carbon 3.
Structure.
(c)
Interpretation:
To draw the structural formula for the compound.
Concept Introduction:
Structural formula is the spatial arrangement of atoms of a molecule in space. In the condensed formula is a line-angle formula, the symbol for carbon and hydrogen atoms are not shown. Only carbon-carbon bonds are shown using lines. Single bonds are shown as 
double bond as 
and triple bond as 
The carbon atoms are represented as vertices and end of lines.
Answer to Problem 12.23P
Explanation of Solution
1,2-Dimethylcyclohexene.
Carbons in longest chain=6.
Cyclo means a cyclic hydrocarbon.
-ene means a double bond is present at Carbon 1.
Methyl at Carbon 1 and 2.
Structure.
(d)
Interpretation:
To draw the structural formula for the compound.
Concept Introduction:
Structural formula is the spatial arrangement of atoms of a molecule in space. In the condensed formula is a line-angle formula, the symbol for carbon and hydrogen atoms are not shown. Only carbon-carbon bonds are shown using lines. Single bonds are shown as 
double bond as 
and triple bond as 
The carbon atoms are represented as vertices and end of lines.
Answer to Problem 12.23P
Explanation of Solution
Trans-3,4-Dimethyl-3-heptene.
Carbons in longest chain=7.
-ene means a double bond is present at Carbon3.
Methyl at Carbon 3 and 4.
Trans isomer that means the two methyl are opposite in direction.
Structure.
(e)
Interpretation:
To draw the structural formula for the compound.
Concept Introduction:
Structural formula is the spatial arrangement of atoms of a molecule in space. In the condensed formula is a line-angle formula, the symbol for carbon and hydrogen atoms are not shown. Only carbon-carbon bonds are shown using lines. Single bonds are shown as 
double bond as 
and triple bond as 
. The carbon atoms are represented as vertices and end of lines.
Answer to Problem 12.23P
Explanation of Solution
Cyclopropene.
Carbons in longest chain=3.
-ene means a double bond is present at Carbon1.
Cyclo means a cyclic hydrocarbon.
Structure.
(f)
Interpretation:
To draw the structural formula for the compound.
Concept Introduction:
Structural formula is the spatial arrangement of atoms of a molecule in space. In the condensed formula is a line-angle formula, the symbol for carbon and hydrogen atoms are not shown. Only carbon-carbon bonds are shown using lines. Single bonds are shown as 
double bond as 
and triple bond as 
. The carbon atoms are represented as vertices and end of lines.
Answer to Problem 12.23P
Explanation of Solution
3-Hexyne.
Carbons in longest chain=6.
-yne means a triple bond is present at Carbon3.
Structure.
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Chapter 12 Solutions
Introduction to General, Organic and Biochemistry
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