Prescott's Microbiology
10th Edition
ISBN: 9781259281594
Author: Joanne Willey, Linda Sherwood Adjunt Professor Lecturer, Christopher J. Woolverton Professor
Publisher: McGraw-Hill Education
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Chapter 11.6, Problem 4RIA
Summary Introduction
The Entner-Doudoroff (ED) pathway is active during the
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Chapter 11 Solutions
Prescott's Microbiology
Ch. 11.1 - Retrieve, Infer, Apply Discuss the ways in which...Ch. 11.1 - Describe the nutritional requirements of the major...Ch. 11.1 - Retrieve, Infer, Apply Compare...Ch. 11.1 - Retrieve, Infer, Apply What are the three major...Ch. 11.2 - Is NAD+ reduced to NADH in the catabolic or...Ch. 11.2 - Prob. 1RIACh. 11.2 - Why is it to a cells advantage to catabolize...Ch. 11.2 - Prob. 3RIACh. 11.4 - Which reactions are examples of substrate-level...Ch. 11.4 - For what kinds of reactions is NADPH used?
Ch. 11.4 - For what macromolecule is ribose 5-phosphate a...Ch. 11.4 - Summarize the major features of the...Ch. 11.4 - Prob. 2RIACh. 11.5 - Identify the substrate and products of the TCA...Ch. 11.5 - What chemical intermediate links pyruvate to the...Ch. 11.5 - Prob. 3RIACh. 11.5 - Retrieve, Infer, Apply In what eukaryotic...Ch. 11.5 - Why is it desirable for a microbe with the...Ch. 11.6 - Prob. 1MICh. 11.6 - Prob. 2MICh. 11.6 - Prob. 1RIACh. 11.6 - Describe the current model of oxidative...Ch. 11.6 - Prob. 3RIACh. 11.6 - Prob. 4RIACh. 11.7 - Prob. 1RIACh. 11.7 - Prob. 2RIACh. 11.7 - Prob. 3RIACh. 11.8 - Prob. 1MICh. 11.8 - Prob. 1RIACh. 11.8 - Prob. 2RIACh. 11.8 - Briefly describe alcoholic, lactic acid, mixed...Ch. 11.8 - Prob. 4RIACh. 11.8 - Prob. 5RIACh. 11.9 - What is the difference between a hydrolase and...Ch. 11.9 - Prob. 2MICh. 11.9 - Retrieve, Infer, Apply Briefly discuss the ways in...Ch. 11.9 - Prob. 2RIACh. 11.9 - Retrieve, Infer, Apply Describe how a...Ch. 11.10 - How do chemolithotrophs obtain their ATP and...Ch. 11.10 - Prob. 2RIACh. 11.10 - Why can hydrogen-oxidizing bacteria and archaea...Ch. 11.10 - What is reverse electron flow and why do many...Ch. 11.10 - Arsenate is a compound that inhibits...Ch. 11.11 - When electrons from P700 are used to reduce NADP+,...Ch. 11.11 - Define the following terms: light reactions, dark...Ch. 11.11 - Prob. 2RIACh. 11.11 - What is the function of accessory pigments?Ch. 11.11 - Prob. 4RIACh. 11.11 - Compare and contrast anoxygenic phototrophy and...Ch. 11.11 - Prob. 6RIACh. 11 - Without looking in chapters 21 and 22, predict...Ch. 11 - From an evolutionary perspective, discuss why most...Ch. 11 - How would you isolate a thermophilic...Ch. 11 - Certain chemicals block ATP synthesis by allowing...Ch. 11 - Prob. 5CHICh. 11 - A cyanobacterium having photosystem I but not...Ch. 11 - Review the description of the Berkeley Pit Lake in...Ch. 11 - The archaeon Metallosphaera sedula is of great...Ch. 11 - Nitrite-oxidizing bacteria have been thought to be...
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- Design a grafting experiment to determine if limb mesoderm determines forelimb / hindlimb identity. Include the experiment, a control, and an interpretation in your answer.arrow_forwardThe Snapdragon is a popular garden flower that comes in a variety of colours, including red, yellow, and orange. The genotypes and associated phenotypes for some of these flowers are as follows: aabb: yellow AABB, AABb, AaBb, and AaBB: red AAbb and Aabb: orange aaBB: yellow aaBb: ? Based on this information, what would the phenotype of a Snapdragon with the genotype aaBb be and why? Question 21 options: orange because A is epistatic to B yellow because A is epistatic to B red because B is epistatic to A orange because B is epistatic to A red because A is epistatic to B yellow because B is epistatic to Aarrow_forwardA sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forward
- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
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