Biology (MindTap Course List)
11th Edition
ISBN: 9781337392938
Author: Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 11, Problem 6TYU
Red–green color blindness is an X-linked recessive disorder in humans. Your friend is the daughter of a color-blind father. Her mother had normal color vision, but her maternal grandfather was color-blind. What is the probability that your friend is color-blind? (a) 1 (b) ½ (c) ¼ (d) ¾ (e) 0
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
A common kind of red-green blindness in humans is caused by the presence of a sex-linked recessive gene c, whose normal allele is c+. Using these genes, what are the possible genotypes and their corresponding phenotypes in males and females? Can two colorblind parents produce a normal son? (b) A normal daughter? (c) Can two normal parents produce a colorblind son? (d) a colorblind daughter?
Red-green color blindness is an X-linked recessive disorder. A woman with normal vision whose father was colorblind has children with a man with normal color vision. What is the probability that their first child will be colorblind?
A) 1/4
B) 1/2
C) 3/4
D) 0
E) 1
Colour-blindness is the result of an X-linked recessive allele, Xc. The allele for normal eyesight is XC.
(a) A woman with normal colour vision whose father was colour-blind marries a colour-blind man. Give the genotypes and phenotypes of their children. What ratio of their children can be expected to be colour-blind?
(b) A man with normal colour vision whose father was colour-blind marries a woman carrier of the colour-blind allele. What is the likelihood that their children will be colour-blind? Carriers of the trait?
Chapter 11 Solutions
Biology (MindTap Course List)
Ch. 11.1 - Define the terms phenotype, genotype, locus,...Ch. 11.1 - Describe Mendels principles of segregation and...Ch. 11.1 - Distinguish among monohybrid, dihybrid, and test...Ch. 11.1 - Explain Mendels principles of segregation and...Ch. 11.1 - What is the maximum number of different alleles...Ch. 11.1 - Can Mendels principle of segregation be...Ch. 11.1 - Prob. 3CCh. 11.2 - PREDICT Use the rules of probability to answer the...Ch. 11.2 - In answering the previous question, did you use...Ch. 11.3 - Define linkage and relate it to specific events in...
Ch. 11.3 - Show how data from a two-point test cross can be...Ch. 11.3 - Discuss the genetic determination of sex and the...Ch. 11.3 - What ratio of genotypes to phenotypes is observed...Ch. 11.3 - Prob. 2CCh. 11.3 - CONNECT Two loci exhibit 5% recombination between...Ch. 11.3 - Which chromosome determines the male sex in humans...Ch. 11.3 - Prob. 5CCh. 11.4 - Explain some of the ways genes may interact to...Ch. 11.4 - Distinguish among incomplete dominance,...Ch. 11.4 - Prob. 11LOCh. 11.4 - Prob. 1CCh. 11.4 - What is the difference between multiple alleles...Ch. 11.4 - Prob. 3CCh. 11.4 - Prob. 4CCh. 11 - One of the autosomal loci controlling eye color in...Ch. 11 - The F1 flies described in question 1 were mated...Ch. 11 - The type of cross described in question 2 is (a)...Ch. 11 - Individuals of genotype AaBb were crossed with...Ch. 11 - Assume that the ratio of females to males is 1:1....Ch. 11 - Redgreen color blindness is an X-linked recessive...Ch. 11 - When two long-winged flies were mated, the...Ch. 11 - The long hair of Persian cats is recessive to the...Ch. 11 - Mr. and Mrs. Smith are concerned because their own...Ch. 11 - A walnut comb rooster is mated to three hens. Hen...Ch. 11 - Individuals of genotype AaBb were mated to...Ch. 11 - Genes A and B are 6 map units apart, and A and C...Ch. 11 - VISUALIZE Sketch a series of diagrams showing each...Ch. 11 - Can you always ascertain an organisms genotype for...Ch. 11 - CONNECT Compare the mechanisms of genetic...Ch. 11 - EVOLUTION LINK Darwins theory of evolution by...Ch. 11 - INTERPRET DATA Using the graph in Figure 11-20,...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Albinism in humans is inherited as a simple recessive trait. For the following families, determine the genotypes of the parents and offspring. (When two alternative genotypes are possible, list both.) (a) Two normal parents have five children, four normal and one albino. (b) A normal male and an albino female have six children, all normal. (c) A normal male and an albino female have six children, three normal and three albino. (d) Construct a pedigree of the families in (b) and (c). Assume that one of the normal children in (b) and one of the albino children in (c) become the parents of eight children. Add these children to the pedigree, predicting their phenotypes (normal or albino).arrow_forwardIn humans, cystic fibrosis is a disease caused by a recessive allele (). Individuals with normal (wildtype) phenotype have the genotype (F). If two heterozygous individuals marry and have 8 children, what is the probability that: a) four will be normal and four will have cystic fibrosis? b) one will have cystic fibrosis and seven will be normal? c) All eight children will have cystic fibrosis?arrow_forwardAlbinism, lack of pigmentation in humans, results from an autosomal recessive gene (a). Two parents with normal pigmentation have an albino child. (a) What is the probability that their next child will be albino? (b) What is the probability that their next child will be an albino girl? (c) What is the probability that their next three children will be albino?arrow_forward
- Glucose-6-phosphate dehydrogenase deficiency (G6PD) is inherited as a recessive allele of an X-linked gene in humans. A woman whose father suffered from G6PD marries a normal man.(a) What proportion of their sons is expected to be G6PD?(b) If the husband was not normal but was G6PD deficient, would you change your answer in part (a)arrow_forwardTwo linked genes, (A) and (B), are seperated by 15 cM. A man with the genotype AB/ab has children with a woman who is ab/ab. The man's father was AB/AB. a) what is the probability that their first child will be Ab/ab b) what is the probability that their first two children will both be ab/abarrow_forwardIn humans, the genetic disease cystic fibrosis is caused by a recessive allele (a). The normal (healthy) allele is dominant (A). What is the genotype of someone who has cystic fibrosis? What are the two different genotypes that a healthy person could have? If two people were both heterozygous for the cystic fibrosis gene, what fraction of their children would be likely to have this disease? Hint: Draw a Punnett square to figure it out.arrow_forward
- In humans, dark hair (D) is dominant over blondness (d), and color blindness (c) is a sex-linked recessive trait. A woman has a blond brother, a blond mother, and a dark-haired father. Her brother and her parents have normal vision. She bears the following three children by her blond, normal-visioned husband: a dark-haired son with normal vision, a dark-haired daughter with normal vision, and a dark-haired color blind son. Make a pedigree of the entire family showing the probable genotypes of all individuals.arrow_forwardIn humans, dark hair (D) is dominant over blondness (d), and color blindness (c) is a sex-linked recessive trait. A woman has a blond brother, a blond mother, and a dark-haired father. Her brother and her parents have normal vision. She bears the following three children by her blond, normal-visioned husband: a dark-haired son with normal vision, a dark-haired daughter with normal vision, and a dark-haired color blind son. What is the probability that her next (fourth) child will be a colorblind boy.arrow_forwardIn humans, dark hair (D) is dominant over blondness (d), and color blindness (c) is a sex-linked recessive trait. A woman has a blond brother, a blond mother, and a dark-haired father. Her brother and her parents have normal vision. She bears the following three children by her blond, normal-visioned husband: a dark-haired son with normal vision, a dark-haired daughter with normal vision, and a dark-haired color blind son. If he is a colorblind boy, what is the probability that he will have dark hair?arrow_forward
- A man who is an achondroplastic dwarf with normal vision marries a color-blind woman of normal height. The man's father was 6 feet tall, and both the woman's parents were of average height. Achondroplastic dwarfism is autosomal dominant, and red-green color blindness is X-linked recessive. a) How many of their daughters might be expected to be color-blind dwarfs? b)What proportion of their sons would be color-blind and of normal height? c)They have a daughter who is a dwarf with normal color vision. What is the probability that she is heterozygous for both genes?arrow_forwardRed-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___arrow_forwardIn humans, the allele for red-green color blindness is X-linked and recessive. An XY man with normal color vision marries a color-blind XX woman who gives birth to a XX color-blind daughter. A] What is the phenotype and genotype ratios possible for a child born to this couple. B] What is the probability that the second XX daughter of this same couple will also be color blind? C] What is the probability that the next child this couple produces together will be a color-blind XY son? D] What can you tell me about the first color-blind daughter born?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSONBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxAnatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
- Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & CompanyLaboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
Animal Communication | Ecology & Environment | Biology | FuseSchool; Author: FuseSchool - Global Education;https://www.youtube.com/watch?v=LsMbn3b1Bis;License: Standard Youtube License