Chapter 11, Problem 11.71SP

Interpretation Introduction

Interpretation:

The Henrys law constant of ${\text{H}}_{\text{2}}\text{S}$ and its solubility in water at ${\text{0}}^{\text{o}}\text{C}$ has to be calculated.

Concept introduction:

Effect of pressure on solubility:

Henrys law:

According to Henrys law, the solubility of a gas in a liquid at a given temperature is directly proportional to the partial pressure of the gas over the solution.

$\begin{array}{l}\text{Solubility}(\text{M)}\text{=}\text{k }\text{. P}\\ \text{where,}\\ \text{k}\text{is}\text{the}\text{constant,}\text{it}\text{expression}\text{is}\text{characteristic}\text{of}\text{a}\text{specific}\text{gas}\\ \text{P is the partial pressure of the gas over the solution}\end{array}$