Chapter 11, Problem 11.48SP

(a)

Interpretation Introduction

Interpretation:

The preparation of given concentration of Glucose in water solution has to be given

Concept introduction:

The concentration of solution can be defined in terms of molarity as the moles of the solute to the volume of the solution.

$\text{Molarity}\text{(in}\text{M)}\text{=}\frac{\text{moles}\text{of}\text{solute}\text{(in}\text{moles)}}{\text{volume}\text{of}\text{solution}\text{(in}\text{litres)}}$

(b)

Interpretation Introduction

Interpretation:

The preparation of given concentration of $\text{KBr}$ in water solution has to be given

Concept introduction:

Molality of a solution also called as molal concentration can be defined as the mass of solute in grams to the mass of the solvent in kilograms. It can be given by the equation,

$\text{Molality}\text{(mol}{\text{kg}}^{\text{-1}}\text{)}\text{=}\frac{\text{Mass}\text{of}\text{solute}\text{(in}\text{g)}}{\text{Mass}\text{of}\text{solvent}\text{(in}\text{kg)}}$

(c)

Interpretation Introduction

Interpretation:

The preparation of given solution of methyl alcohol and water has to be given

Concept introduction:

Mole fraction of a compound can be defined as the number of moles of a substance to the total number of moles present in them. The mole fraction can be calculated by,

$\text{Mole}\text{fraction}\text{of}\text{compound}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{(in}\text{mol)}}{\text{Total}\text{number}\text{of}\text{moles}\text{(in}\text{mol)}}$