Chapter 11, Problem 11.126CHP

(a)

Interpretation Introduction

Interpretation:

The mass of the given precipitate in grams has to be calculated.

Concept Introduction:

The mass of the precipitate can be calculated using below the formula.

$\text{mass}\text{=}\text{mole ×}\text{molecular}\text{weight}$

(b)

Interpretation Introduction

Interpretation:

Whether the addition of more of ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ to the filtrate obtained from the given solution will give more precipitate or not has to be explained.